The sigma-70 promoter is very well-studied. The Sigma-54 promoter, on the other hand, hasn't hadquite as much study devoted to it, but a consensus sequence for Sigma-54 promoters has beendetermined, and it looks like this:CGAAAFICGCACTECTУАC5-26-25-24 -23 -22 -21 -20 -19 -18 -17 -16-15-14-13-12-11 -10 3wablogo berkalay.edu(From Franke et. Al, 2011 BMC Genomics)If you were studying a gene with a promoter that exactly matched the consensus sequence, whichbase would, if mutated, probably make the largest difference in the ability of Sigma-54 to bind to apromoter?O Base position 26Base position 10Base position 12Base position 16

Answer :- Sigma factors are crucial proteins in bacterial transcription, responsible for guiding RNA…

The sigma-70 promoter is very well-studied. The Sigma-54 promoter, on the other hand, hasn't had quite as much study devoted to it, but a consensus sequence for Sigma-54 promoters has been determined, and it looks like this: C FIGCCACATCCT AGGG 5-26-25-24-23-22 -21 -20 -19 -18 -17 -16-15-14-13-12-11 -10 3 wablogo.berkalay.edu

The sigma-70 promoter is very well-studied. The Sigma-54 promoter, on the other hand, hasn't had quite as much study devoted to it, but a consensus sequence for Sigma-54 promoters has been determined, and it looks like this: C FIGCCACATCCT AGGG 5-26-25-24-23-22 -21 -20 -19 -18 -17 -16-15-14-13-12-11 -10 3 wablogo.berkalay.edu

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 10QP: The pre-mRNA transcript and protein made by several mutant genes were examined. The results are...

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The following segment of DNA is part of the RNA-coding sequence of a transcription unit. If the bottom strand is template, which of the following RNA sequences would be transcribed? DNA: 5-'ATAGGCGATGCCA-3' 3'-TATCCGCTACGGT-5' O 5'-UAUCCGCUACGGU-3' O 5'-ACCGUAGCGGAUA-3' O 5'-AUAGGCGAUGCCA-3' O 5'-UGGCAUCGCCUAU-3'
You have isolated a mutant that you call Mutant Z. In a Mutant Z strain, the RNA polymerase can bind to the promoter, but it does not stay bound (e.g. it can only bind reversibly). A mutation in which of the following cis elements could lead to the Mutant Z phenotype? (you may select more than one option) Oribosome binding site O-35 promoter region Odomain 2 of sigma 3/4 linker of sigma -10 promoter region Odomain 1 of sigma Olac repressor Odomain 4 of sigma
Which of the following statements is/are TRUE for the promoters? The Pribnow box and TATA box are found in the prokaryotes and eukaryotes, respectively. For both prokaryotes and eukaryotes, the first ribonucleotide attaches to the TSS region. The -35 element in prokaryotes is called the Up element in eukaryotes. In prokaryotes, the Pribnow box is located 25 bases before TSS.
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT O The mutation would bind the promoter to the consensus and produce normal levels of transcription O The mutation would inhibit the promoter thereby inhibiting transcription The mutation would move the promoter away from consensus and reduce the level of transcription O No change the consensus TATAAT sequence in the same. D00 F3 F4 F5 F6 F7 F8 F9 % & 5 6 7 8 9 %24
Which of the following is a property or characteristic of eukaryotic promoters? They contain the -10 and-35 consensus sequences where RNA polymerase holoenzyme, containing the sigma factor, bind to initiate transcription. | They contain the -10 and -35 consensus sequences that are the site where general transcription factors bind to help RNA polymerase holoenzyme initiate transcription. They contain a TATA box to which sigma factors bind to help RNA polymerase core enzyme initiate transcription. O I. They are usually located far away from the gene that is being transcribed. IV. OV. A, They are bound by general transcription factors, which help RNA polymerase I, II, or III, bind to the promoter and initiate transcription.
Match the following terms related to transcription in eukaryotes (you may use terms more than once or not at all) A) RNA Polymerase I, B) RNA Polymerase II, C) RNA Polymerase III, D) All 3 RNA Polymerases E) None of the above 1. Driven only by downstream promoter elements __________ 2. Promoter contains TATA box __________ 3. rRNA __________ 4. tRNA __________ 5. mRNA __________ 6. snRNA __________ 7. A second class of promoters contains CAAT box 100-200 nucleotides from the start site of transcription __________ 8. Synthesize RNA 5’ to 3’ __________ 9. Synthesizes RNA 3’ to 5’ __________ 10. Very sensitive to α-amanitin __________
A bacterial species has a hypothetical sigma promoter that has the following sequence: TTGGCA - 18 bases - TATAAT What change in the level of transcription would there be if the sequence was mutated to: TTCGCA -18 bases -TATAAT Group of answer choices 1.The mutation would inhibit the promoter thereby inhibiting transcription 2.No change the consensus TATAAT sequence in the same. 3.The mutation would move the promoter away from consensus and reduce the level of transcription 4.The mutation would bind the promoter to the consensus and produce normal levels of transcription
The diagram below shows an imaginary eukaryotic structural gene containing two exons. The exon nucleotides are numbered beginning at the transcription start site and a portion of the intron is not shown to save space: Help Center? transcription start site promoter U STACAGTATAAATGAATTAATTGACGTATGTCAATCGGTAAGT...TCAGGTACT U UUU} Phe UUG} Leu exon 1 3 ATGTCATATTTACTTAATTAACTGCATACAGTTAGCCATTCA...AGTCCATGAATGACTTATGTGCGGTTATTTACTGAT... Second letter C Predict the amino acid sequence of the polypeptide encoded by this structural gene. The genetic code is provided below.
Consider the following sequence fragment of an mRNA. Which of the miRNAS below would be competent for gene silencing? 5'-AUGCAAGCAUUGGCCAAGCUU-3' 5'-AUGCAAGCAUUGGCCAAGCUU-3 5'-UACGUUCGUAACCGGUUCGAA-3' 5'-AAGCUUGGUUAAUGCUUGCAU-3' 5'-UUCGAACCAAUUACGAACGUA-3' 3'-UUCGAACCAAUUACGAACGUA-5 3'-AUGCAAGCAUUGGCCAAGCUU-5'
Which of the following is a likely outcome of Rifampin treatment? Transcriptional elongation is blocked Peptidyltransferase activity is inhibited at the ribosome The peptidoglycan cell wall is degraded by peptidoglycan hydrolases Double stranded DNA breaks Pore formation in the outer membrane
If the promoter is here and transcription starts here 5' -GTATAAAАTGATACGTCTСТAGСТАGCTАGCTAGGAACCOАGСТAGCTАCGTAGGGCATG-3' 3'-САТАТТTАСТАТGCAGAGTAGAATCGATCGATCCТTGGGTOGATCGATGCATСССGТАС-5" what are the first 4 bases of the RNA, written from 5' to 3'? ОА. UCGA О в. UCGU ОС. AGCU О D. AGCT