the result is T=3;C=3;x=5;z=0%; A= (x^2+3*C*cos(z)-2)/8*sqrt (abs (T^2-x^2)); fprintf('T=%2d\tC=%2d\t_A=%3.2f',T,C,A) 33 A=16.00 T= 3 C= 3 A= 16.00 T= 3 C= 3 A= 16 O T=3;C=3 : A=16
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- (p^-p) = F Ture FalseFincd O A/B A = @ A./B %3D 23 5.The cateve cede x_m= [0;d b = [4₁2] L = [00;20] D = [3020 51 u U = [0 -1; 0 0 True Fallse Fac bdash = inv (L+D) *b; B = inv (L+D) * (°; For n = 2:44 2 x_m=bdash - B*x_m end for Jok p can be executed in order to apply three iteration of the Gauss-Seidel method, taking the initial approximetticD 20995 babisión P 3x₁ - x₂ = -4 2X1 +502 = 2 44 OR ان انار (0) X₁₁² =0=X₂₁₂²², to approximate the solution of the system 2 اوران
- Evaluate the following exPvessious m= 6, uz2 a z0, bz0,C-o, d-o, and e=o (i) at=4+ cii) bキ=3+ --m*mj siii) ct= 2 tm * ++m; civ) d* = 2* tm*m--; くV)e--ュ2巻++m/m--i(x^2)/2 + (x^3)/3_5.Q(2): Given a quadratic equation, 2 x^2-3 x+1=O, the roots of this equation are given by, x= (-b±v(b^2-4ac))/2a. find the roots x1 and x2 using command windows or script file of matlab program. Upload the program as pdf file .with the results
- 11:1Y VO 2.png t 2-y Q1: Find lim y- o 7+6y2 Q2: Find for y= (4x² +12)*(3x-20)² Q3: Find dy for y= sin2x cosx +x cos2xpA(p V q) = q Ture FalseComputer Science Flowchart for this code Please C PROGRAM : #include unsigned int x; sbit P11 = P1^1; main() { unsigned char xdata *ELET212; ELET212 = 0×FC48; %3D %3D *ELET212=0XFE; P11=0; while(1) { for(x=0; x<10000; x++); P11="P11; }