The quadratic function, f(x) = (x + 1)² +9, is shown in the graph below.This quadratic does not have real roots, but rather a pair of complex roots. The rootsof f(x) take the form a ± bi where i is the imaginary unit.Solve for the roots and input the integer values of a and b below:a =10b =

The given quadratic equation is

The quadratic function, f(x) = (x + 1)² +9, is shown in the graph below. 10 a = 15 b = 10 0 This quadratic does not have real roots, but rather a pair of complex roots. T of f(x) take the form a ± bi where i is the imaginary unit. Solve for the roots and input the integer values of a and b below: B 10 신

The quadratic function, f(x) = (x + 1)² +9, is shown in the graph below. 10 a = 15 b = 10 0 This quadratic does not have real roots, but rather a pair of complex roots. T of f(x) take the form a ± bi where i is the imaginary unit. Solve for the roots and input the integer values of a and b below: B 10 신

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter12: Quadratic Functions

Section12.4: Graphs Of Quadratic Equations: The Discriminant

Problem 18WE

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