The program written for binary search, calculates the midpoint of the span as mid: = (Low + High)/2. The program works well if the number of elements in the list is small (about 32,000) but it behaves abnormally when the number of elements is large. This can be avoided by performing the calculation as:
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- The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…Write a function that takes in n ADT Lists in an array. The function is going to be called Intersection, and it will return a new list with the elements common to all the n lists. Determine the time complexityIn Python: Write a recursive function named Multiply2 that multiples by 2 and prints each element in a given list. For example: mylist=[1,2,3,4] Multiply2(mylist) prints: 2 4 6 8 Note: the function takes only one parameter, which is the list on which the operation will be performed. It's ok if the list becomes empty after calling the function.
- nums = [9,-8,7,-6,3,2,-1,3,10,9] Use enumerate to iterate through the index and values of the nums list, and output the index where userNum is found. For example, if userNum is 3, your output should be: Number 3 found at index 4 Number 3 found at index 7Write a function that takes a nested list of integers and add up the elements from all of the nested lists.MASM IRVINE 32 library PROGRAM. How do you take a SORTED array of elements and count the amount of each integer in that list and then display it. So if i had a list of [1,2,4,1,4,2,1,4,1,2,4,5,2]. I need to make a program that can iterate through that and find the amount of 1s, 2s, 3s, 4s etc and display it. MUST BE IN MASM IRVINE 32 LIBRARY.
- Up for the count def counting_series(n): The Champernowne word 1234567891011121314151617181920212223... is an infinitely long string of digits made up of all positive integers written in ascending order without any separators between the individual numbers. This function should return the integer digit that lies in the position n of the Champernowne word, position count again starting from zero as usual. Of course, the automated tester will give your function values of n large enough that anybody trying to solve this problem by explicitly constructing the series as a string would run out of time and space long before receiving the answer. Instead, you should observe that the structure of this infinite sequence is quite straightforward, as it starts with 9 single-digit numbers, followed by 90 two-digit numbers, followed by 900 three-digit numbers, and so on. Such a predictably self-similar structure allows you to skip over prefixes of this series in exponentially widening leaps and…Up for the count def counting_series(n): The Champernowne word 1234567891011121314151617181920212223... is an infinitely long string of digits made up of all positive integers written in ascending order without any separators between the individual numbers. This function should return the integer digit that lies in the position n of the Champernowne word, position count again starting from zero as usual.Of course, the automated tester will give your function values of n large enough that anybody trying to solve this problem by explicitly constructing the series as a string would run out of time and space long before receiving the answer. Instead, you should observe that the structure of this infinite sequence is quite straightforward, as it starts with 9 single-digit numbers, followed by 90 two-digit numbers, followed by 900 three-digit numbers, and so on. Such a predictably self-similar structure allows you to skip over prefixes of this series in exponentially widening leaps and…In this programming exercise you will implement two functions. The first function will prompt the user for a file containing the number of vertices and entries of the adjacency matrix of a graph. It will return a two-dimensional list (a list of lists) containing the adjacency matrix. The textfile is named inputfilename.txt am trying to read for the matrix [[0, 1, 2, 3, 100, 100, 100, 100], [1, 0, 2, 100, 3, 4, 100, 100], [2, 2 0, 4, 4, 100, 5, 100], [3, 100, 4, 0, 100, 100, 4, 100], [100, 3, 4, 100, 0, 3, 3, 3], [100, 4, 100, 100, 3, 0, 100, 1], [100, 100, 5, 4, 3, 100, 0, 2], [100, 100, 100, 100, 3, 1, 2, 0]] def readMatrix(inputfilename): ''' Returns a two-dimentional array created from the data in the given file. Pre: 'inputfilename' is the name of a text file whose first row contains the number of vertices in a graph and whose subsequent rows contain the rows of the adjacency matrix of the graph. ''' # Open the file f =…
- Programming language : Java Write the program the should determine if there exists a 3 partition of the given list, P1, P2, and P3 such that the sum of the elements in P1 minus the sum of the elements in P2 are exactly k and the sum of the elements in P2 minus the sum of the elements in P3 are also exactly k. k is a positive integer, or zero. P1, P2, and P3 are the partitions such that |sum(P1) - sum(P2)| = k and |sum(P2) - sum(P3)| = k. For example if list is given below: 1. List = [3 1 3 2 1] k = 4 Output: True The 3 partition form above list which satifies the condition is: P1 = {2}, P2 = {3, 3}, P3 = {1, 1} Sum(P1) = 2 Sum(P2) = 6 Sum(P3) = 1 + 1 = 2 |Sum(P1) - Sum(P2)| = 4 |Sum(P2) - Sum(P3)| = 4 2. List = [49 49 36 44 43 49 48 36 32 26 38] k = 88 Output: True A 3 partition that works is…Write a function sum_alt that takes a list of numbers zand calculates their alternating sum, defined as n-1 Σ(-1)+1 zk. k=0 Here Zo, Z1, Zn-1 denote the individual elements of the list.Write the function selection_sort_descend_trace() that takes an integer list and sorts the list into descending order. The function should use nested loops and output the list after each iteration of the outer loop, thus outputting the list N-1 times (where N is the size). Complete __main__ to read in a list of integers, and then call selection_sort_descend_trace() to sort the list. Ex: If the input is: 20 10 30 40 then the output is: 40 10 30 20 40 30 10 20 40 30 20 10 Here is original Code: # TODO: Write a selection_sort_descend_trace() function that # sorts the numbers list into descending orderdef selection_sort_descend_trace(numbers): if __name__ == "__main__":# TODO: Read in a list of integers into numbers, then call# selection_sort_descend_trace() to sort the numbersnumbers = []