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The monthly income I, in dollars, from a new product is given by I(t)=8100-6500e-0.002t where t is the time, in months, since the product was first put on the market. (a) What was the monthly income after the 10th month and after the 100th month? (Round your answers to the nearest cent.) I(10) = $ I(100) = $ (b) What will the monthly income from the product approach as the time increases without bound? $

The monthly income I, in dollars, from a new product is given by I(t)=8100-6500e-0.002t where t is the time, in months, since the product was first put on the market. (a) What was the monthly income after the 10th month and after the 100th month? (Round your answers to the nearest cent.) I(10) = $ I(100) = $ (b) What will the monthly income from the product approach as the time increases without bound? $

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 40E
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The monthly income I, in dollars, from a new product is given by I(t) = 8100 6500e-0.002t where t is the time, in months, since the product was first put on the market. (a) What was the monthly income after the 10th month and after the 100th month? (Round your answers to the nearest cent.) I(10) = $ I(100) = $ (b) What will the monthly income from the product approach as the time increases without bound? $
Transcribed Image Text:The monthly income I, in dollars, from a new product is given by I(t) = 8100 6500e-0.002t where t is the time, in months, since the product was first put on the market. (a) What was the monthly income after the 10th month and after the 100th month? (Round your answers to the nearest cent.) I(10) = $ I(100) = $ (b) What will the monthly income from the product approach as the time increases without bound? $
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