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- M EXPERIMENT 01 V(n002) V(n001) 10V- 8V- 6V- 4V- 2V- OV- -2V- 4V- -6V- -8V- -10V- 0.00ms 30.00ms 60.00ms 90.00ms 120.00ms 150.00ms 180.00ms K EXPERIMENT 01 X Diode 1N914 V Resistor SINE(0 10 60000 100) 10K .tran 2Intrinsic breakdown occurs in time of the order of 10* -5 s 10 *5 s 10*-8 s 10*8 s Within dielectric, an electron starting from the cathode will drift towards the anode and during this motion Gains energy from the field and loses during collision Gains energy during both motion and collision Loses energy during both motion and collision Loses energy from the field and gains during collisionexplain the process of the following Positive pulses Positive edges
- * For a clamper circuit, if the input is the blue waveform and the output is the red one. Scale 5V/Div. Determine the correct operation circuit XPG1 MA S a 1 C1 10μF XFC1 AVAFE HH D1 1N4001 VI 5V 3 R1 $10k C1 10μF XFG1 50 2 D1 1N4001* V1 6V C1 10μF D1 1N4001 V1 10V R1 Σ10kΩ R1 >10K 3 O 1 O 2Calculate the output voltage for the circuit given. The value of input voltage can be taken as 2mV, load resistor has a value of 10K Ohm and Beta has a value of 100. You MUST include the value of re' in the calculations. Please make wave-forms at each point. Vcc +20V Rc 3.3 kN C3 33 k2 out I µF RE 330 N ER2 10 ΚΩ RE2 330 2 C2 10 μFThe voltage minima in Smith chart always lie on * r=0 r=100 r=10
- Refer to Figure If 50V is applied across the capacitors, determine Q. Write the answer in mC 30 μF 60 µF 20 µF ▬HE HE C₁ C2 C 3 -Given the circuit and the input waveform, what is the charge voltage across the capacitor express answer in volts 4" 0 20 V -20 V 64 Vi C 10V + R V 19The value of capacitor increases with O increase in the thickness of insulating material decrease in the thickness of insulating material O decrease in the value of dielectric coefficient decrease in the area of conducting plates