The inverse Fourier transform of the position probability amplitude y(x,t) is: a. w(p.t): O b. y (k,t) OC. d. w (x,t) = w(p,t) = 1 2π ħ 1 2r ħ 1 2r ħ 1 P + x - Sto ÿ (x,1) e " dp - 00 2π ħ - S + 0 % ( (x,t) e - 00 S. ·S+ a - 00 P + (k.1) e ² = 2 * ak dk + ∞o - S y - 00 P ħ₂. dx (x,t) e -²x dx

Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter6: Quantum Mechanics In One Dimension
Section: Chapter Questions
Problem 24P
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The inverse Fourier transform of the position probability amplitude y(x,t) is:
a.
w(p.t):
O b.
y (k,t)
OC.
d.
w (x,t) =
w(p,t) =
1
2π ħ
1
2r ħ
1
2r ħ
1
P
+
- Sto ÿ (x,1) e "
- 00
2π ħ
- S + 0 % ( (x,t) e
- 00
S.
- 00
P
·S+ a + (k.1) e ² = 2 * ak
dk
+ ∞o
- S y
- 00
x
(x,t) e
dp
P
ħ₂. dx
-²x
dx
Transcribed Image Text:The inverse Fourier transform of the position probability amplitude y(x,t) is: a. w(p.t): O b. y (k,t) OC. d. w (x,t) = w(p,t) = 1 2π ħ 1 2r ħ 1 2r ħ 1 P + - Sto ÿ (x,1) e " - 00 2π ħ - S + 0 % ( (x,t) e - 00 S. - 00 P ·S+ a + (k.1) e ² = 2 * ak dk + ∞o - S y - 00 x (x,t) e dp P ħ₂. dx -²x dx
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