The hypotenuse of a 30°-60°-90° triangle has a length of 20 cm. Which could be the length of a leg of the triangle? Select all that apply. OA 10 cm OB. 12 cm OC. 16 cm OD. 10√3 cm

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A: volume(V)=13BHwhere B is base area H is height

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A: Consider

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A: Given that length of AB =length of DC, AC=9 and DE=4

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A: tanC=oppositeadjecent

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A:

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A: In the diagram, DE¯ is parallel to AB¯. Let DC = 15, AC = 27, and CE = 12.5

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A: cosx=basehypotenuse in ∆UTS(UT)2+((ST)2=(US)2

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A: Given figure:-

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A: Please see the below picture for detailed solution.

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A: Area of the segment=θ360°πr2-12r2sinθ  Substitute θ=60° , r=9

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Q: Find the measurement indicated to the nearest tenth. A 22⁰ x B 4 C

A: We can use the trignometry function to find the value of x tanθ = perpendicularbase