The Haber-Bosch process is a very important industrial process. In the Haber-Bosch process, hydrogen gas reacts with nitrogen gas to produce ammonia according to the equation 3H₂(g) + N₂(g)+2NH3(g) The ammonia produced in the Haber-Bosch process has a wide range of uses, from fertilizer to pharmaceuticals. However, the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation. 1.90 g H₂ is allowed to react with 10.3 g N₂. producing 2.31 g NH₂. Part A What is the theoretical yield in grams for this reaction under the given conditions? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) 9.97 HÅ g 850 ?
The Haber-Bosch process is a very important industrial process. In the Haber-Bosch process, hydrogen gas reacts with nitrogen gas to produce ammonia according to the equation 3H₂(g) + N₂(g)+2NH3(g) The ammonia produced in the Haber-Bosch process has a wide range of uses, from fertilizer to pharmaceuticals. However, the production of ammonia is difficult, resulting in lower yields than those predicted from the chemical equation. 1.90 g H₂ is allowed to react with 10.3 g N₂. producing 2.31 g NH₂. Part A What is the theoretical yield in grams for this reaction under the given conditions? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) 9.97 HÅ g 850 ?
General Chemistry - Standalone book (MindTap Course List)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter21: Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 21.200QP
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The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
Question
![The Haber-Bosch process is a very important industrial process.
In the Haber-Bosch process, hydrogen gas reacts with nitrogen
gas to produce ammonia according to the equation
3H₂(g) + N₂(g) →2NH3(g)
The ammonia produced in the Haber-Bosch process has a wide
range of uses, from fertilizer to pharmaceuticals. However, the
production of ammonia is difficult, resulting in lower yields than
those predicted from the chemical equation.
MISSED THIS? Watch KCV 7.4, IWE 7.4; Read Section 7.4. You
can click on the Review link to access the section in your eText.
Hydrobromic acid dissolves solid iron according to the followiaung
reaction:
Fe(s) + 2HBr(aq) → FeBr2(aq) + H₂(g)
MISSED THIS? Watch KCV 7.4, IWE 7.4: Read Section 7.4. You
can click on the Review link to access the section in your e Text.
Hydrobromic acid dissolves solid iron according to the followiaung
reaction:
Fe(s) + 2HBr (aq) → FeBr₂ (aq) + H₂(g)
1.90 g H₂ is allowed to react with 10.3 g N₂. producing 2.31 g NHS.
Part A
What is the theoretical yield in grams for this reaction under the given conditions?
Express your answer to three significant figures and include the appropriate units.
View Available Hint(s)
9.97
▼
Part A
HÅ
m =
X Incorrect; Try Again; 9 attempts remaining
Part B
4
What mass of H₂ would the complete reaction of the iron bar produce?
Express your answer in grams to three significant figures.
▸View Available Hint(s)
[5] ΑΣΦ
m= 9.3
.13.
C
What mass of HBr (in g) would you need to dissolve a 3.7-g pure iron bar on a padlock?
Express your answer in grams to three significant figures.
► View Available Hint(s)
195| ΑΣΦ
?
g
8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4eeec424-2c95-4e8f-949a-2df80720674d%2Fc2bd2279-f986-4c51-9952-5caf05ecb6b8%2Fketymq_processed.png&w=3840&q=75)
Transcribed Image Text:The Haber-Bosch process is a very important industrial process.
In the Haber-Bosch process, hydrogen gas reacts with nitrogen
gas to produce ammonia according to the equation
3H₂(g) + N₂(g) →2NH3(g)
The ammonia produced in the Haber-Bosch process has a wide
range of uses, from fertilizer to pharmaceuticals. However, the
production of ammonia is difficult, resulting in lower yields than
those predicted from the chemical equation.
MISSED THIS? Watch KCV 7.4, IWE 7.4; Read Section 7.4. You
can click on the Review link to access the section in your eText.
Hydrobromic acid dissolves solid iron according to the followiaung
reaction:
Fe(s) + 2HBr(aq) → FeBr2(aq) + H₂(g)
MISSED THIS? Watch KCV 7.4, IWE 7.4: Read Section 7.4. You
can click on the Review link to access the section in your e Text.
Hydrobromic acid dissolves solid iron according to the followiaung
reaction:
Fe(s) + 2HBr (aq) → FeBr₂ (aq) + H₂(g)
1.90 g H₂ is allowed to react with 10.3 g N₂. producing 2.31 g NHS.
Part A
What is the theoretical yield in grams for this reaction under the given conditions?
Express your answer to three significant figures and include the appropriate units.
View Available Hint(s)
9.97
▼
Part A
HÅ
m =
X Incorrect; Try Again; 9 attempts remaining
Part B
4
What mass of H₂ would the complete reaction of the iron bar produce?
Express your answer in grams to three significant figures.
▸View Available Hint(s)
[5] ΑΣΦ
m= 9.3
.13.
C
What mass of HBr (in g) would you need to dissolve a 3.7-g pure iron bar on a padlock?
Express your answer in grams to three significant figures.
► View Available Hint(s)
195| ΑΣΦ
?
g
8
Transcribed Image Text:Melamine, C3 N3 (NH2)3, is used in adhesives and resins. It is
manufactured in a two-step process in which urea, CO (NH₂)2,
is the sole starting material, isocyanic acid, HNCO, is an
intermediate, and ammonia, NH3, and carbon dioxide, CO2,
gases are byproducts.
In the first step of this reaction, urea is broken down into isocyanic acid and ammonia:
▼
Part A
CO(NH2)2(1)—HNCO(1)+NH3(g)
In the second step of this reaction, isocyanic acid reacts to form melamine and carbon dioxide:
HNCO (1)→C3 N3 (NH2)3 (1) + CO2(g)
Balance this reaction and enter the coefficients below.
Enter the coefficients in order separated by commas (e.g., 1, 4, 5, where 1 indicates the lack of a coefficient).
View Available Hint(s)
Rev
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