The gas-phate reaction 2 N₂O₂(g) 4 NO₂ (8) + 0₂ (8) has an activation energy of 103 k/mol, and the rate constant is 0.0900 min at 328.0 K Find the rate constant at 304 8 K. The value of gas constant is 8.3145 x 10 kJ/K mol Rate constant- min-1

Chemistry: Matter and Change
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Chapter16: Reaction Rates
Section16.3: Reaction Rate Laws
Problem 26SSC
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The gas-phate reaction
2 N₂Os(8)→ 4NO₂ (s) + O₂(8)
has an activation energy of 103 kJ/mol, and the rate constant is 0.0900 min at 328.0 K. Find the rate constant at 304 8 K. The value of gas constant is 8.3145 x 10 kJ/K-mol
Rate constant =
min-¹
Transcribed Image Text:The gas-phate reaction 2 N₂Os(8)→ 4NO₂ (s) + O₂(8) has an activation energy of 103 kJ/mol, and the rate constant is 0.0900 min at 328.0 K. Find the rate constant at 304 8 K. The value of gas constant is 8.3145 x 10 kJ/K-mol Rate constant = min-¹
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