The formation constant* of [M(CN)614 is 2.50 × 10¹7, where M is a generic metal. A 0.160 mole quantity of M(NO3)2 is added to a liter of 1.330 M NaCN solution. What is the concentration of M2+ ions at equilibrium? [M²+] = 1.56 X10-16 Incorrect Attempt 1 M
The formation constant* of [M(CN)614 is 2.50 × 10¹7, where M is a generic metal. A 0.160 mole quantity of M(NO3)2 is added to a liter of 1.330 M NaCN solution. What is the concentration of M2+ ions at equilibrium? [M²+] = 1.56 X10-16 Incorrect Attempt 1 M
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter17: Solubility And Complex-ion Equilibria
Section: Chapter Questions
Problem 17.127QP
Related questions
Question
![The formation constant* of [M(CN)614 is 2.50 × 10¹7, where M is a generic metal.
A 0.160 mole quantity of M(NO3)2 is added to a liter of 1.330 M NaCN solution.
What is the concentration of M2+ ions at equilibrium?
[M²+] =
1.56 X10-16
Incorrect
Attempt 1
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0897122a-db53-42c7-8552-415933c864eb%2Fde9c9fe2-89b7-4278-9372-2aec8728d1fe%2F81lfn2f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The formation constant* of [M(CN)614 is 2.50 × 10¹7, where M is a generic metal.
A 0.160 mole quantity of M(NO3)2 is added to a liter of 1.330 M NaCN solution.
What is the concentration of M2+ ions at equilibrium?
[M²+] =
1.56 X10-16
Incorrect
Attempt 1
M
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