The force applied on a body to lift it up 0.0028 kg.m/s2, convert this value of Force into g.ft/min². (Hint: For entering the answer with power, for e.g. 5.0x10-5 use 5.0E-5) 0.0028 Kg. m/s2 = g. ft/min2

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Energy Of A System
Section6.3: The Scalar Product Of Two Vectors
Problem 6.3QQ: Which of the following statements is true about the relationship between the dot product of two...
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The force applied on a body to lift it up 0.0028 kg.m/s², convert this value of Force into g.ft/min².
(Hint: For entering the answer with power, for e.g. 5.0x10-5 use 5.0E-5)
0.0028 Kg. m/s2 =
g. ft/min²
Transcribed Image Text:The force applied on a body to lift it up 0.0028 kg.m/s², convert this value of Force into g.ft/min². (Hint: For entering the answer with power, for e.g. 5.0x10-5 use 5.0E-5) 0.0028 Kg. m/s2 = g. ft/min²
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