The following thermochemical equation is for the reaction of tetraphosphorus decaoxide(s) with water(I) to form phosphoric acid(aq). P4O10(s) + 6H20- 4H3PO4(aq) AH=-453 kJ How many grams of P4O10(s) would have to react to produce 173 kJ of energy?

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter8: Thermochemistry
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Problem 65QAP: Natural gas companies in the United States use the therm as a unit of energy. One therm is 1105 BTU....
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The following thermochemical equation is for the reaction of tetraphosphorus decaoxide(s) with water(I) to form phosphoric acid(aq).
P,010(s) + 6H20)
4H3PO4(aq)
AH=-453 kJ
How many grams of P4010(s) would have to react to produce 173 kJ of energy?
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Transcribed Image Text:[References] Use the References to access important values if needed for this question. The following thermochemical equation is for the reaction of tetraphosphorus decaoxide(s) with water(I) to form phosphoric acid(aq). P,010(s) + 6H20) 4H3PO4(aq) AH=-453 kJ How many grams of P4010(s) would have to react to produce 173 kJ of energy? grams Submit Answer Try Another Version 3 item attempts remaining
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