The following table shows the normal time, crash time, normal cost, and crash cost of an activity. What is the cost of reducing the activity's duration by 5 time units Normal time Crash time Normal cost Crash cost 30 10 $150 $350
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- What is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 days? Normal Cost $800 $200 $600 $750 $1,200 Normal Crash Activity Time (days) Time (days) 4 3 8 6 The total cost of crashing the project by 4 days is $ ABCDE 487 355 (Enter your response as a whole number.) Total Cost with Crashing Immediate Predecessor(s) $1,500 $1,650 By how many days should each activity be crashed to reduce the project completion time by 4 days? Fill in the table below. (Enter your responses as whole numbers.) Each Activity Should be Reduced BY (days) Activity A B C D E $1,100 $600 $650 A CWhat is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 days? Normal Crash Time Activity Time (days) (days) AB А C D E 67555 5 BCD w 55 с 4 2 Activity A E 3 Normal Cost $800 $300 $600 $750 $1,200 Immediate Total Cost with Crashing Predecessor(s) $1,100 $500 By how many days should each activity be crashed to reduce the project completion time by 4 days? Fill in the table below. (Enter your responses as whole numbers.) $650 $1,500 $1,650 - Each Activity Should be Reduced BY (days) A CWhat is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 days? Crash Normal Activity Time (days) Time (days) Normal Cost A 5 4 B 9 7 C 6 5 D 7 5 E 7 4 Total Cost with Crashing Immediate Predecessor(s) $800 $300 $600 $750 $1,200 By how many days should each activity be crashed to reduce the project completion time by 4 days? Fill in the table below. (Enter your responses as whole numbers.) Each Activity Should be Reduced BY (days) Activity A B C D E $1,100 $400 $650 $1,500 $1,650 | | | < 0
- Consider the following activity description with associated cost data shown in Table 1. The cost data represents the total cost and should be considered linear with time. Table 1: Crash Cost Table Activity Immediate Predecessor Normal Duration (days) Normal Cost ($) Crash Duration (days) Crash Cost ($) A --- 5 50 3 150 B --- 4 40 2 200 C B 7 70 5 250 D A, C 2 20 1 50 E A, C 5 125 1 525 F B 10 80 7 290 G D 7 50 3 250 H E, F 6 60 3 180 Reduce the project duration to minimum duration and calculate the cost. Note:- Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. Answer completely. You will get up vote for sure.Activity normal durations, crash durations and cost Activity Normal Duration (weeks) Crash Duration (weeks) Normal Cost ($) Crash Cost ($) A-B 4 2 300,000.00 420,000.00 B-C 3 3 100,000.00 100,000.00 B-D 2 1 50,000.00 55,000.00 B-E 6 5 150,000.00 200,000.00 C-F 3 2 30,000.00 150,000.00 C-K 3 2 20,000.00 25,000.00 D-G 2 1 300,000.00 350,000.00 E-H 10 8 60,000.00 140,000.00 F-G 3 2 160,000.00 260,000.00 F-I 3 2 350,000.00 500,000.00 F-K 2 1 170,000.00 270,000.00 F-L 2 1 330,000.00 440,000.00 F-N 2 1 250,000.00 500,000.00 G-L 2 1 60,000.00 65,000.00 H-K 10 9 100,000.00 110,000.00 I-J 2 1 10,000.00 20,000.00 J-O 3 1 30,000.00 35,000.00 K-N 8 7 50,000.00 80,000.00 L-M 4 2 40,000.00 50,000.00 M-O 2 1 5,000.00 6,000.00 N-O 12 10 200,000.00 240,000.00 Note: The Crash duration represents the minimum duration where an activity is speeded up as much as possible. The crash cost represents the increased cost…Create a risk matrix for this project:Event Cost ($000) ProbabilityEquipment breakdown 40 .20Vendor is late with key segment 200 .60Subcontractor has labor issues 140 .30Weather problems 15 UnknownFunding delays 50 .40 to .60Testing delays 20 .40Explain your reasoning for your placement of the events Weather problems and Funding delays.
- D. The information related to project crashing is shown in the following table. Normal Crash Duration Normal Duration Crash Activity (hours) Cost (S) (hours) Cost ($) 2 10 2 10 B 3 15 2 23 C 25 28 20 24 6. 30 45 F 1 5 35 50 10 50 7 80 If we want to reduce the project duration by 3 hours, what will be the cost of crashing?Activity Normal_time Crash_time Normal_cost Crash_cost Slack A 31 17 4800 6200 В 14 14 5500 5500 C 34 18 5100 6600 21 17 4500 6800 E 15 15 5300 5300 F 17 17 5300 5300 The table shows normal time, crash time, normal cost, crash cost and slack time of activities in a project. According to this table which activity must be crashed first? Assume there is only one critical path. (Only type the name of the activity, Example: A. @orsdemir. Copyrighted content. Cannot be posted.) 0ㅇ11 2 0Development of Version 2.0 of a particular accounting software product is being considered by Jose Noguera's technology firm in Baton Rouge. The activities necessary for the completion of this project are listed in the following table: Total Cost Normal Time Crash Time Normal with Immediate Activity (weeks) (weeks) Cost Crashing Predecessor(s) $2,200 $2,100 $2,900 $2,900 A 4 3 1 C 3 3 $500 $500 $2,500 $1,000 $3,200 $2,800 $1,375 $4,600 $2,100 8. E 6. 3 G 4 $1,600 D, E a) Based on the given information regarding the activities for the project, the project length = weeks. %3D b) The total cost required for completing this project on normal time = $ %3D c) For reducing the duration of the project by one week, the activity that should be crashed first is activity The cost of the project based on the first activity selected for crashing will increase by $ d) The maximum weeks by which the project can be reduced by crashing = weeks. %3D Total cost of crashing the project to minimum (or…
- The following represents a project that should be scheduled using CPM: TIMES (DAYS) ACTIVITY IMMEDIATE PREDECESSORS ABCDEFGH G H A A-D-G-H A-C-F-H B-E-G-H A-D-F-H A B C,D D, E F,G b. What is the critical path? a 1 1 1 2 3 3 1 2 m 3 2 2 3 4 4 4 4 D53341565 b 11Development of Version 2.0 of a particular accounting software product is being considered by Jose Noguera's technology firm in Baton Rouge. The activities necessary for the completion of this project are listed in the following table D Total Cost with Normal Time Crash Time Normal Immediate Activity (weeks) (weeks) Cost Crashing Predecessor(s) A 4 3 $2,000 $2,650 B 2 1 $2,300 $3,100 TTTT C 3 3 $750 $750 D 8 4 $2,300 $2,580 A E 6 3 $1,000 $1,300 B F 3 2 $3,000 $4,400 C G 4 2 $1,600 $2,000 D, E a) Based on the given information regarding the activities for the project, the project length = weeks. b) The total cost required for completing this project on normal time = $ ▼ c) For reducing the duration of the project by one week, the activity that should be crashed first is activity The cost of the project based on the first activity selected for crashing will increase by $ weeks. d) The maximum weeks by which the project can be reduced by crashing = Total cost of crashing the project to…In the project considered below, activity crashing can take place over a wide range of reduction times. The cost per day of reduction is given: Activity Immediate Normal Time Cost/day Lower Time Predecessor (days) Limit A None 3 450 1 B None 4 300 2 A 3 200 D E 100 E A,B 500 1 F C.D 4 600 3 For example, activity C can be crashed from its normal time of 3 days down to as little as 1 day or anywhere in between; the cost per day to crash C is 200. a) Draw a network diagram for this project. What is the critical path? How long will the project take, if no crashing takes place? b) Determine the least cost way to crash activities in order to complete the project in 11 days; in 10 days; in 9 days; in 8 days. c) Suppose the due date for the project is 5 days and a penalty of $500 a day is assessed for each day late. What is the optimal number of days to crash the project? Why?