The following equilibrium constants were determine at 2400K: HI(g) → H2(g) + 12 (s) H(g) → H2(g) 12 (s) → (8) Kc = Kp = 6.71e-4 = 3.38e10 = Kp = i) Find K, for: HI(g) → H(g) + (g) at 2400 K? Kp = 3.00e-2 Use correct number of significant figures but no units. Use the format 6.02e-6 ii) If 1.00 mg of H, I and HI are placed in a 10.0L vessel at 2400K, what is Q Use correct number of significant figures but no units. Use the format 6.02e-6 iii) what direction will the reaction proceed? L = Left, R = Right, NC = No change Reaction shift = Type, L, R or NC
The following equilibrium constants were determine at 2400K: HI(g) → H2(g) + 12 (s) H(g) → H2(g) 12 (s) → (8) Kc = Kp = 6.71e-4 = 3.38e10 = Kp = i) Find K, for: HI(g) → H(g) + (g) at 2400 K? Kp = 3.00e-2 Use correct number of significant figures but no units. Use the format 6.02e-6 ii) If 1.00 mg of H, I and HI are placed in a 10.0L vessel at 2400K, what is Q Use correct number of significant figures but no units. Use the format 6.02e-6 iii) what direction will the reaction proceed? L = Left, R = Right, NC = No change Reaction shift = Type, L, R or NC
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.45PAE: The following equilibrium is established in a closed container: C(s)+O2(g)CO2(g)H=393kJmol1 How does...
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Transcribed Image Text:The following equilibrium constants were determine at 2400K:
HI(g) → H2(g) + 12 (s) Kp = 6.71e-4
H(g) → H2(g)
12 (s) → (8)
Kc
Kp = 3.38e10
i) Find K, for: HI(g) → H(g) + (g) at 2400 K?
Q=
Kp
= 3.00e-2
Reaction shift =
ii) If 1.00 mg of H, I and HI are placed in a 10.0L vessel at 2400K, what is Q
Use correct number of significant figures but no units. Use the format 6.02e-6
Use correct number of significant figures but no units. Use the format 6.02e-6
iii) what direction will the reaction proceed? L = Left, R = Right, NC = No change
Type, L, R or NC
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