The following code implements Newton's algorithm for finding the square root of a number using repetition: 17 # we want the square root of 17 for example # our guess is 4 initially # we want to stop when we g = 4 error 0.0000000001 are thi close while abs (n (g**2)) > error: ( (g**2 n)/(2 g)) g = g # g holds the square root ofn at this point Implement this algorithm in a function sqRoot (n, g, e), that returns the square root using recursion. Assume that the function will be called with positive numbers only.
The following code implements Newton's algorithm for finding the square root of a number using repetition: 17 # we want the square root of 17 for example # our guess is 4 initially # we want to stop when we g = 4 error 0.0000000001 are thi close while abs (n (g**2)) > error: ( (g**2 n)/(2 g)) g = g # g holds the square root ofn at this point Implement this algorithm in a function sqRoot (n, g, e), that returns the square root using recursion. Assume that the function will be called with positive numbers only.
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter4: Selection Structures
Section: Chapter Questions
Problem 14PP
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We are trying to find the square root using RECURSION. Look at the instructions.
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