The figure here shows a plot of potential energy U versus position x of a 0.888 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, Ug = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.04 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.04 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? UcT UB UA U (J)

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter8: Conservation Of Energy
Section: Chapter Questions
Problem 55PQ: A particle moves in one dimension under the action of a conservative force. The potential energy of...
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The figure here shows a plot of potential energy U versus position x of a 0.888 kg particle that can travel only along an x
axis. (Nonconservative forces are not involved.) Three values are Ug = 15.0 J, Ug = 35.0 J and Uc = 45.0 J. The particle is
released at x = 4.50 m with an initial speed of 7.04 m/s, headed in the negative x direction. (a) If the particle can reach x
= 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction
of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the
positive x direction when it is released at x = 4.50 m at speed 7.04 m/s. (d) If the particle can reach x = 7.00 m, what is
its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on
the particle as it begins to move to the right of x = 5.00 m?
Uc
UB
UA
4
6
x (m)
(a) Number
Unit
(b) Number
Unit
(c)
(d) Number
Unit
(e) Number
Unit
(f)
Click
positive (+x)
ke to Show Work for this question: Open Show Work
negative (-x)
alicy
000-ZUzi Junn Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc.
Transcribed Image Text:The figure here shows a plot of potential energy U versus position x of a 0.888 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are Ug = 15.0 J, Ug = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.04 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.04 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? Uc UB UA 4 6 x (m) (a) Number Unit (b) Number Unit (c) (d) Number Unit (e) Number Unit (f) Click positive (+x) ke to Show Work for this question: Open Show Work negative (-x) alicy 000-ZUzi Junn Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc.
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