The failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0, calculate the maximum load in N that the bar can support. A 12500*pi (B 6250*pi C) 3125*pi 1563*pi
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- 3) An bronze rod is rigidly attached between a aluminum rod and a steel rod as shown. Axial loads are applied at the positions indicated. Find the maximum allowable value of P that will not exceed a stress in steel of 140MPA, in aluminum of 90MPA or in bronze of 100MPа. Aluminum A = 500mm? Bronze A = 200mm? Steel A = 150mm2 2P ЗР L st = 1.2m L br = 2m Lal = 3.5mThe failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0, calculate the maximum load in N that the bar can support. A 12500*pi B 6250*pi 3125*pi 1563*piThe shown plate is 60 mm thick and it is made of Magnesium Am1004-T61. The plate is fitted between the rigid frictionless supports as shown and at T, = 20°C it is stress free. Find the stresses in the x and y directions when the temperature increases to T, = 58°C. %3D 150 mm 150 mm Select one: O x: 0 MPa, y: 42.864 MPa Ox: 22.1 MPa, y: 44.2 MPa Ox: 0 MPa, y: 44.2 MPa Ox: 0 MPa, y: 17.8 MPa O x: 13.2 MPa, y: 44.2 MPa Ox: 0 MPa, y: 67.4 MPa 3:10 PM O G 4) ENG 1/31/2021
- q7 A steel bar 2 m long, 20 mm wide and 15 mm thick is subjected to a tensile load of 30 kN. If Poisson's ratio is 0.25 and Young's modulus is 200 GPa, an increase in volume will be (b) 150 mm3 (d) 130 mm3 (a) 160 mm3 (c) 140 mm3An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm A = 400mm? A- 200mm 40KN 10KN 20KN 1.5m 2.5m 2.0m Determine the change in length of steel rod having a length of 800mm and a diameter of 6.5mm. The rod is subjected to a force P equal to 110KN. Young's Modulus is 200GPA Compute normal strain of the rodThe failure stress of a homogeneous steel bar having a diameter of 10 mm is 250 MPa. Using a factor of safety of 2.0, calculate the maximum load in N that the bar can support. А) 12500-pi в) 6250*pi с) 3125*pi D) 1563*pi
- An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm? A = 400mm? A - 200mm 40KN 10KN 20KN 2.5m 2.0m 1.5mA steel bar 30 mm in diameter and 2 m long is encased in a shell of cast iron 5 mm thick. Compute the stress in each material, in MPa, if a compressive axial load of 150 kN is applied to the assembly. For steel, E = 200 MPa and for cast iron, E = 100 %3D GPa ( Select the correct response(s): 29.96 MPa 76.39 MPa 212.21 MPa 106.10 MPa 136.32 MPa 152.79 MPa 59.92 MPa 272.84 MPaA 4.8ft-long steel wire of 1/4in-diameter is subjected to a 750lb-Tensile load. Knowing that E=29x10^6psi, determine (a) the elongation of the wire, and (b) the corresponding normal stress.
- Two plate are joint by five rivets of 20 mm diameter. What is the shear stress in the material if the shear forces is 18840 N O 12 N/mm2 O 20 N/mm2 O 15 N/mm2Situation 2 For the assembly shown, determine the stress in each of the two vertical rods if the temperature rises 40°C after the load P=50 KN is applied. Neglect the deformation and the mass of the horizontal bar AB. Compute the vertical movement under the load. Steel Aluminum E=200 GPa E=70 GPa L-4m A=300 mm? a-11.7x10*/°C L-3m A=900 mm a=23x10“ /°C 3 m 3 m 3 m Situation 32. A rod is composed of an aluminum section rigidly attached between steel and bronze sections as shown in the figure. Axial loads are applied at the positions indicated. The cross-sectional area of the rod is 300sq.mm. Express your answer in MPa. Determine the stress in the steel. b. a. Determine the stress in the aluminum. Determine the stress in the bronze. C. STEEL ALUMINUM BRONZE 56kN 14kN -0.6m- -0.9m- -0.76m-