The F1 will display no phenotypic variation for this characteristic All phenotypic variation for this characteristic in F2 can be attributed to the environment The F2 will be genetically uniform for this characteristic The individuals in F1 will have the same genotype for this characteristic

The F1 will display no phenotypic variation for this characteristic All phenotypic variation for this characteristic in F2 can be attributed to the environment The F2 will be genetically uniform for this characteristic The individuals in F1 will have the same genotype for this characteristic

Name: Alp Following a cross of two pure-breeding lines that differ in a quan
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Description: Alp Following a cross of two pure-breeding lines that differ in a quantitative characteristic, what is true?The F1 will display no phenotypic variation for this characteristicAll phenotypic variation for this characteristic in F2 can be attributed to

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter19: Population Genetics And Human Evolution

Section: Chapter Questions

Problem 11QP: Using the HardyWeinberg Law in Human Genetics In a given population, the frequencies of the four...

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A bean breeder is working with a population in which themean number of pods per plant is 50 and the variance is10 pods2. The broad-sense heritability is known to be 0.8.Given this information, can the breeder be assured thatthe population will respond to selection for an increase inthe number of pods per plant in the next generation?
In Ayrshire cattle, the spotting of the coat can be either red andwhite or mahogany and white. The mahogany-and-white phenotypeis caused by the allele SM (where the letter S indicates spotting, andthe superscript M stands for mahogany). The red-and-white phenotypeis controlled by the allele SR (where the superscript R standsfor red). The table below shows the relationships between genotypeand phenotype for males and females: Explain the pattern of inheritance.
Figure 19-11 shows the expected distributions for thethree genotypic classes if the B locus is a QTL affectingthe trait value.a. As drawn, what is the dominance/additive (D/A)ratio?b. How would you redraw this figure if the B locus hadno effect on the trait value?c. How would the positions along the x-axis of thecurves for the different genotypic classes of the B locuschange if D/A = 1.0?
In a plant, fruit color is either red or yellow, and fruit shape iseither oval or long. Red and oval are the dominant traits. Twoplants, both heterozygous for these traits, were testcrossed, withthe results shown in the following table. Determine the locationof the genes relative to one another and the genotypes of the twoparental plants. ProgenyPhenotype Plant A Plant Bred, long 46 4yellow, oval 44 6 red, oval 5 43yellow, long 5 47Total 100 100
In codominance, O there are always more than two alleles for a given character in a population O the heterozygote is an intermediate phenotype between the parental phenotypes O the heterozygote exhibits the phenotypes of both parents equally the two alleles affect more than one aspect of the phenotype
Seed weight in a particular plant species is determined by pairs of alleles attwo loci (a+ a− and b+ b−) that are additive and equal in their effects. Plantswith genotype a− a− b− b− have seeds that average 1 g in weight, whereasplants with genotype a+ a+ b+ b+ have seeds that average 3.4 g in weight. Aplant with genotype a− a− b− b− is crossed with a plant of genotype a+ a+ b+b+.a. What is the predicted weight of seeds from the F1 progeny of this cross?b. If the F1 plants are intercrossed, what are the expected seed weights andproportions of the F2 plants?
Two traits with similar phenotypic variance exist in apopulation. One trait has two major genes and sixminor loci that influence the phenotypic value, andthe second trait has 12 minor loci and no major genesaffecting the phenotypic value. Does this informationtell you which trait you should expect to respondmost consistently to selection? Explain why it doesor does not.
Estimates of broad sense heritability for the commercially important trait "first lactation milk" in dairy cows have nearly doubled from ~0.25 in the 1970's to ~0.4 today. Which of the following can explain this increase? All of these can explain the increase O The number of genes impacting the first lactation milk phenotype is higher now than it was in the 1970s Dairy cows are reared in more uniform environments now than they were in the 1970s O Dairy cows are more genetically uniform now than they were in the 1970s
The ABO blood group has three different alleles: F, P, and i. The genotypes and phenotypes (blood types) for different combinations of the three alleles are shown in the table. Possible Genotype and Phenotypes of ABO Blood Group Phenotypes (Blood types) Type A Туре В Туре О Type AB Genotypes AJA or Ai BIB or 1Bi JAJB What percentage of offspring from a cross between a homozygous Type B parent with a Type AB parent is expected to contain the i allele? O A. 25% ов 0% ос. 75% O D. 100% acer
A large, genetically heterogeneous group of tomato plants was usedas the original breeding stock by two different breeders, namedMary and Hector. Each breeder was given 50 seeds and began aselective breeding strategy, much like that described in Figure24.11. The seeds were planted, and the breeders selected the 10plants with the highest mean tomato weights as the breeding stockfor the next generation. This process was repeated over the courseof 12 growing seasons, and the following data were obtained: A. Explain these results.B. Another tomato breeder, named Martin, got some seeds fromMary’s and Hector’s tomato strains (after 12 generations),grew the plants, and then crossed them to each other. The mean weight of the tomatoes in these hybrids was about 1.7 pounds.For a period of 5 years, Martin subjected these hybrids to thesame selective breeding strategy that Mary and Hector had followed,and he obtained the following results: Explain Martin’s data. Why was Martin able to obtain…
chickens, comb shape is determined by alleles at twa loci (R. And P.) Walnut comb is produced w atan one dominant allele Is present at one locus and at least one dominant allele Pis present at a second locus Prototype. A rose comb is produced when at least one dominant allele is present at the first locus and two recessive alletes are present at the second locus (genotype: Rpp). A pea comb is produced when two recessive alleles are present at the first locus and at least one dominant allele is present at the second (genotypes wa recessive alleles are present at the first and at the second locus trap), a single comb is produced Progeny with what types of combs and in what proportions will result from the cross between Rp and PP 14 Walnut Pol 1/4 rose comb (Ppl. 1/4 Pea comb (rrPp), 1/4 single comb (rrpp) 16 walnut, 3/16 rosecomb (pp. 3/16 pea.comb (P X. 1/16 single comb (rrpp) O34 rose comb (R PP), 1/4 single comb rrpp) 12 walnut (RPp), 1/2 rose comb (Rpp). O pea (Pp). O single comb…
The ABO blood group has three different alleles: F, P, and i. The genotypes and phenotypes (blood types) for different combinations of the three alleles are shown in the table. Possible Genotype and Phenotypes of ABO Blood Group Genotypes Phenotypes (Blood types) JAJA or Ai Type A al 10 glal Type B |Туре О ii AJB Type AB What percentage of offspring from a cross between a homozygous Type B parent with a Type AB parent is expected to contain the i allele? O A. 25% о в 0% ос. 75% O D. 100%