The evaporation of one mole of water at 298 K has a standard free energy change of 8.58 kJ.H2O(l) ⇌ H2O(g)                  ΔG°298 = 8.58 kJ(a) Is the evaporation of water under standard thermodynamic conditions spontaneous?(b) Determine the equilibrium constant, KP, for this physical process.(c) By calculating ΔG, determine if the evaporation of water at 298 K is spontaneous when the partial pressure of water, PH2 O, is 0.011 atm.(d) If the evaporation of water were always nonspontaneous at room temperature, wet laundry would never dry when placed outside. In order for laundry to dry, what must be the value of PH2 O in the air?

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Chapter18: Thermodynamics And Equilibrium
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The evaporation of one mole of water at 298 K has a standard free energy change of 8.58 kJ.
H2O(l) ⇌ H2O(g)                  ΔG°298 = 8.58 kJ
(a) Is the evaporation of water under standard thermodynamic conditions spontaneous?
(b) Determine the equilibrium constant, KP, for this physical process.
(c) By calculating ΔG, determine if the evaporation of water at 298 K is spontaneous when the partial pressure of water, PH2 O, is 0.011 atm.
(d) If the evaporation of water were always nonspontaneous at room temperature, wet laundry would never dry when placed outside. In order for laundry to dry, what must be the value of PH2 O in the air?

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