The equilibrium constant expression for the reaction: CS₂(g) + 4H₂(g) → CH4(g) + 2H₂S(g) is: O Kc = [CS₂] [H₂] / [CH4] [H₂S] OK[CS₂] 4[H₂1] / [CH4] 2[H₂S] OK. (CS₂] [H₂] / [CH4] [H₂S]² O Kc = [CH4] [H₂S] / [CS₂] [H₂] OK. [CH4] 2[H₂S] / [CS₂]4[H₂] OK[CH₂] [H₂S]²/[CS₂] [H₂14
The equilibrium constant expression for the reaction: CS₂(g) + 4H₂(g) → CH4(g) + 2H₂S(g) is: O Kc = [CS₂] [H₂] / [CH4] [H₂S] OK[CS₂] 4[H₂1] / [CH4] 2[H₂S] OK. (CS₂] [H₂] / [CH4] [H₂S]² O Kc = [CH4] [H₂S] / [CS₂] [H₂] OK. [CH4] 2[H₂S] / [CS₂]4[H₂] OK[CH₂] [H₂S]²/[CS₂] [H₂14
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 119AP
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![The equilibrium constant expression for the reaction:
CS₂(g) + 4H₂(g) → CH4(g) + 2H₂S(g)
is:
OK.
[CS₂] [H₂] / [CH4] [H₂S]
OK [CS₂] 4[H₂2] / [CH4] 2[H₂S]
OK. [CS₂] [H₂]/[CH4] [H₂S]²
O Kc = [CH4] [H₂S] / [CS₂] [H₂]
OK [CH4] 2[H₂S] / [CS₂]4[H₂]
OK - [CH] [H₂S]2/[CS₂] [H₂]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff549444a-0c9a-4a07-b0c4-fe0e1b780a66%2F3ffed705-f503-4aac-a17d-ace50855e26d%2Fli8deob_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equilibrium constant expression for the reaction:
CS₂(g) + 4H₂(g) → CH4(g) + 2H₂S(g)
is:
OK.
[CS₂] [H₂] / [CH4] [H₂S]
OK [CS₂] 4[H₂2] / [CH4] 2[H₂S]
OK. [CS₂] [H₂]/[CH4] [H₂S]²
O Kc = [CH4] [H₂S] / [CS₂] [H₂]
OK [CH4] 2[H₂S] / [CS₂]4[H₂]
OK - [CH] [H₂S]2/[CS₂] [H₂]
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