The equations for ideal projectile motion are given as: y(t) = y₁ − 12gt² + (vosin(0))t x(t) = x₁ + (v₂cos (0))t where: y(t) is the vertical distance and, x(1) is the horizontal distance traveled by the projectile in metres g is the acceleration due to Earth's gravity = 9.8 m/s2 and, is time in seconds. Let us assume that the initial velocity of the projectile vo = 50.75 m/s and e projectile's launching angle 0 = 5 radians. The initial vertical and horizontal positions of the projectile are given by yo = 0 m and x = 0 m. Give the values for a) y(t) and b) x(1) given t=0 to = 10 with 0.1 increments, representing time in seconds.

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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The equations for ideal projectile motion are given as:
y(t) = yo 12gt² + (vosin(0))t
x(t) = xo + (vocos (0))t
where:
y(t) is the vertical distance and,
x(t) is the horizontal distance traveled by the projectile in metres
g is the acceleration due to Earth's gravity = 9.8 m/s2 and,
t is time in seconds.
Let us assume that the initial velocity of the projectile vo = 50.75 m/s and the projectile's launching angle 0 = 5 radians. The initial vertical and horizontal positions of the
projectile are given by yo = 0 m and x = 0 m.
Give the values for a) y(t) and b) x(1) given t=0 to 1 = 10 with 0.1 increments, representing time in seconds.
Transcribed Image Text:The equations for ideal projectile motion are given as: y(t) = yo 12gt² + (vosin(0))t x(t) = xo + (vocos (0))t where: y(t) is the vertical distance and, x(t) is the horizontal distance traveled by the projectile in metres g is the acceleration due to Earth's gravity = 9.8 m/s2 and, t is time in seconds. Let us assume that the initial velocity of the projectile vo = 50.75 m/s and the projectile's launching angle 0 = 5 radians. The initial vertical and horizontal positions of the projectile are given by yo = 0 m and x = 0 m. Give the values for a) y(t) and b) x(1) given t=0 to 1 = 10 with 0.1 increments, representing time in seconds.
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