the diagram below, label the: DNA double helix RNA transcript Template strand • Coding strand • 5' and 3' ends of each DNA and RNA strand • GODT K Unwinding Rewinding G BARA RNA-DNA hybrid helix RNA polymerase

the diagram below, label the: DNA double helix RNA transcript Template strand • Coding strand • 5' and 3' ends of each DNA and RNA strand • GODT K Unwinding Rewinding G BARA RNA-DNA hybrid helix RNA polymerase

Name: In the diagram below, label the:DNA double helixRNA transcriptTemplat
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Description: In the diagram below, label the:DNA double helixRNA transcriptTemplate strandCoding strand5' and 3' ends of each DNA and RNA strandRewindingค อ DLRNA-DNA hybrid helixUnwindingRNA polymerase

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 16QP: Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also,...

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40 Shown below is the antisense strand of DNA. What is the amino acid sequence that corresponds to this code? 5' AAAGCATACCGG 3' Second letter G. UUU Phe UCU UAU) Tyr UGC Cys UGU UUC UCC UAC Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUA UCA UUG Leu UG CAU His CGU CGC CGA CGG CU CUU CUC CUA CUG CAC Pro Leu Arg CCA CAA) Gin CCG CAG AAU AUU AUC lle AUA AUG Met ACG ACU AGU AAC Asn AGC Ser ACC ACA Thr AAA1 AGA AAG Lys AGG Arg GAU) Asp GGC GAC Ala GAA GGU GUU GUC GUA Val GCU GCC Gly GCA GGA Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a PRO-VAL-SER-PHE PHE-ARG-MET-ALA GLY-HIS THR-LYS d LYS-ALA-TYR-ARG First letter Third letter
What would the amino acid sequence be for the following DNA Transcript? 5’AAGCCATTTAAAGGC 3’ 3’ TTCGGTAAATTTCCG 5’ Phe Gly Lys Phe Pro Phe Leu Lys Phe Val Lys Phe Phe Lys Pro Lys Pro Phe Lys Gly More information is needed
The BNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U P с > < A G U UUU UUC Phe UUA UUG CUU CUC CUA CUG L GUU GUC GUA GUG Leu Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala Cys UAA Stop UGA Stop A Trp UAG Stop UGG CAC His CGU J CGC CAA I CGA Gin CAGG CGG AAA 1 AAG Lys UGU UGC AAU Asn AGC} AAC GAC Asp GAA GAGGIU For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph V Arial G 1 AGA 1 AGG GGU GGC GGA GGG Arg Ser Arg Gly V DCAG DCA DOA UCAG Third letter 10pt < Av V IX Q ... O WORDS POWERED BY TINY
3’-TCTTCGTGAGATGATATAAGAGTTATCCAGGTACCGGTAAACTGG-5’ 5’-AGAAGCACTCTACTATATTCTCAATAGGTCCATGGCCATTTGACC-3’ Write down the mRNA transcript from DNA above.
What is the RNA transcript that would result from the double stranded DNA segment shown below? 5'-GCACGTTGGTCGATCACGTAATATACGCATCGACTCCCGATCGA-3' 3'-CGTGCAACCAGCTAGTGCATTATATGCGTAGCTGAGGGCTAGCT-5' 5'- ين
Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also, write out the amino acid sequence of the protein encoded by this message. tRNA: UAC UCU CGA GGC mRNA: protein: How many hydrogen bonds would be present in the DNA segment?
Arg-ser-ser-ala-pro Possibilities mRNA 3’ AGG UCA UCU GCU CCC 5’ 5’ ACC ACG CCU CCU GGC 3’ 3’ UCC ACG CCU ACU GGA 5’ 5’ CGC UCC CCU GCC CCC 3’ Possibilities coding strand 5’ TCC TCG ACT GCT GGA 3’ 3’ TCC TCG TGA CGA CGC 5’ 5’ CGG ACT ACT GCA CCA 3’ 3’ CCC ACG ACT CCT CGC 5’ Possibilities non- coding strand 3’ GGG TCA TCA CGG GGG 5’ 5’ TCC AGC AGC CGC GGC 3’ 3’ GCC TCA AGC CGA GGA 5’ 5’ TGG TGC TGA AGA TCA 3’
pcc300ATAAADATATAOOTTAA 1. Use the genetic code table and the information in the diagram below to determine the amino acids that would make up the portion of the polypeptide shown. Include information for a key as well. DNA template 3' G CATA ACAGAGGATT-5' al bnsua AMAm pniwollot erfT E transcription s yd bnsita ebitgeqylog s sidmeaze of beae RNA strandUU UAOUOUU A-emoaodin 5'-CGUA AUUGUC UCCUUA- 3' J J JL erit o elinW (s) translation bluow terdt aspnso sigootiwsone polypeptide viemetis ns ebivo19 (d) ent ot etslanT Key:
Give the RNA molecule sequence transcribed from the following DNA sequence of a eukaryotic gene and with the correct 5' and 3' ends. DNA: 5'-ATAGGGCATGT-3' 3'-TATCCCGTACA-5' <--- template strand Group of answer choices 5'-ATAGGGCATGT-3' 3'-UAUCCCGUACA-5' 5'-AUAGGGCAUGU-3' 3'-TATCCCGTACA-5'
Coding DNA 5’- GTG ACT CGT TGT GCC ATT GCA GCT AAA CAC TTC GAG CCC TGT- 3’ mRNA 5’- GUG ACU CGU UGU GCC AUU GCA GCU AAA CAC UUC GAG CCC UGU- 3’ What is the polypeptide sequence?
The schematic dlagram below shows the functional organization of transcribing RNA polymerase. Match parts of the diagram (labeled A-G) with the corresponding term from the answer list (design ated 1-12). Polymerase movement ANA POLYMERASE A Rowinding of DNA Unwinding of DNA E NTPs Note that some of the items from the answer list should NOT be used. Labels E and F point to the specific ends of DNA/RNA molecules. 1. Template strand 2. RNA transcript 3. Replication origin 4 Non-Template strand 5. Leading strand 6. 3 end 7. Primer 8. Replication fork 9. Transcription bubble 10. 5' end 11. DNA RNA nybrid 12. Lagging strand
BM4_DNA AND PROTEIN S X /1FAIPQLSDP_g5B-629FSHNpGnTMIEppLS4A71zBd4vcUBqNUILubXONw/formResponse 4. What is the nitrogen base pair of Adenine in transcription? O Cytosine O Uracil O guanine O thymine 5. The central dogma of Molecular Biology states that There are four nitrogen bases in DNA, two purines (adenine and guanine) and two pyrimidines (cytosine and thymine). Which process is not included in the central dogma? duplication transcription translation O translocation Leadple