The container 393 M A-Determine the optimum moisture content and the maximum dry unit weight B-what is the dry uhit weight and water content at 95% standard compaction in the field ?
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- A standard Proctor Test has yielded the values shown below. Determine: (a) The maximum dry unit weight and its OMC at Volume of 1/30 cubic ft. (b) The moisture for 93% of maximum dry unit weight. range STANDARD PROCTOR TEST RESULTS TRIAL WEIGHT OF SOIL (Ibs.) MOISTURE (%) |8.24 3.26 4.15 1 10.20 4.67 12.30 4. 4.02 14.60 3.36 16.80 23The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold (cu.m) Wt. of wet soil in mold (kg) Moisture (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content
- A sample soil for proposed building-the engineer in-charge decided to under go soil testing. A 480 cubic centimeter (cc) soil sample taken from the site weighs 850.5 grams. After oven drying, it weighed 594.4 grams. -If the specific gravity of solids is 2.72, what will be the result of the void ratio (e) of the soil? -What will be result in saturation (S)?2) Using the following results: weight of dried pan and sand Is 1.0376 g. weight of pan and liquid sample is 4.6274 g. and weight of the pan and dried sample is 1.7321 g. What was the moisture content of the sample and what is the percent total solids?A dry sand is placed in a ontainer having a volume of 0.366 ft8. the dry weight Of the sample is 34.41b. A volume OF 0.0522 ft3 container so as not to dist urb the condition of the sand 3. OF water is care Fu lly added to the to if the Specific gravity of sand is 2662, determine the. a.) porosity b) Degree of saturation (2 decimal places) c) Bulk specific gravity (3 dlecimal places) (3deuimal places)
- The results of a standard and a modified Proctor tests ate given in the table below. a) Generate a plot of dry unit weight as a function of water content including the zero air voids (ZAV) curve (note that the units are in cm³ and kg). b) Determine the maximum dry unit weight of compaction and the optimum moisture content. Show calculation on how to determine the maximum dry density and the optimum moisture content. STANDARD PROCTOR TEST DATA MODIFIED PROCTOR TEST DATA Volume of Mass of Wet Soil Water Content, Mass of wet soil Water Content, Mold (cm?) in the mold (kg) wC in the mold (kg) wC 1.68 0.099 1.83 0.059 1.71 0.106 1.89 0.066 1.77 0.121 1.95 0.081 1.83 0.138 2.00 0.098 943.3 1.86 0.151 2.03 0.111 1.88 0.174 2.05 0.134 1.87 0.194 2.04 0.154 1.85 0.212 2.00 0.172• Problem 2--- From the following data of the grain size analysis Sieve size #4 #8 #10 #25 #60 #100 # 200 Pan Sieve opening (mm) 4.76 2.36 2.00 0.71 0.25 0.149 0.074 Determine; a) Cu and Cc system % Finer (by weight) 80 56 51 35 18 13 7 ——— b) classify the soil using the unified soil classification1.5 cm datum The following are the results of a compaction test; Mass of mold+wet soil(g) 2925 3095 3150 3125 3070 Water content% 10 12 14.3 16.1 18.2 If the volume of mold = 1000 ml, and mass of mold = 1000 g, and Specific gravit of solids = 2.70. G4 Wc a. Find the compaction curve showing the optimum moisture content and maximu dry density. b. Plot the zero air void line. c. Determine the degree of saturation at the maximum dry density. Sr P COONCOM
- Q7: The Table 4 shows the results of a Standard Proctor Compaction test. Satisfactory Y Based on the information provided, determine the following values. The maximum dry unit weight and the OMC. The degree of saturation at the maximum dry density if Gs = 2.70. What is the dry unit weight and the moisture range at 95% relative compaction (RC)? The degree of saturation at the maximum dry density if Gs = 2.70. Table 4: Results of a standard Proctor compaction test Trial No. 1 4 13.2 Moisture content, w (%) 6.2 8.1 9.8 11.5 12.3 20.1 Bulk unit weight (kN/m³) 16.9 18.7 19.5 20.5 20.4 17.8 Dry unit weight (kN/m³) 15.9 17.3 17.8 18.4 18.2A sample soil for proposed building-the engineer in-charge decided to under go soil testing. A 480 cubic centimeter (cc) soil sample taken from the site weighs 850.5 grams. After oven drying, it weighed 594.4 grams. If the specific gravity of solids is 2.72, what will be result in saturation (S) ?Soil Compaction Problem: The following data were obtained from a Proctor Test: Water | 12 13 14 16 Content (%) Weight of Wet 17 18 18.7 19.3 18.9 Sample (N) The volume of the mold was 9.44 x 10-4 m³ (a) Determine the optimum water content and maximum dry unit weight (b) Plot the zero air voids line (c) Determine the degree of saturation at the maximum dry unit weight.