The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest wavelength corresponding to a transition shown in the figure. त Balmer series ENERGY 11 00 (a) Determine its energy. eV (b) Determine its wavelength. nm (d) Find its wavelength. E (eV) 0.00 nm -0.378 -0.544 2 -0.850 4 -1.512 -3.401 Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure. (c) Find its photon energy. eV Ⓡ (e) What is the shortest possible wavelength in the Balmer series? nm

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The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest
wavelength corresponding to a transition shown in the figure.
ENERGY
11
00
त
Balmer
series
(a) Determine its energy.
eV
(b) Determine its wavelength.
nm
(d) Find its wavelength.
nm
E (eV)
0.00
-0.378
-0.544 2
-0.850 4
-1.512
Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure.
(c) Find its photon energy.
eV
-3.401
(e) What is the shortest possible wavelength in the Balmer series?
nm
Transcribed Image Text:The Balmer series for the hydrogen atom corresponds to electronic transitions that terminate in the state with quantum number n = 2 as shown in the figure below. Consider the photon of longest wavelength corresponding to a transition shown in the figure. ENERGY 11 00 त Balmer series (a) Determine its energy. eV (b) Determine its wavelength. nm (d) Find its wavelength. nm E (eV) 0.00 -0.378 -0.544 2 -0.850 4 -1.512 Consider the spectral line of shortest wavelength corresponding to a transition shown in the figure. (c) Find its photon energy. eV -3.401 (e) What is the shortest possible wavelength in the Balmer series? nm
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