The back tangent AV of a simple curve has an azimuth of 252° while that of its forward tangent VB has an azimuth of 300°. The degree of the simple curve is 4º, arc basis. It is desired to replace the simple curve with another curve having 100 m spirals at its end. Without changing the points of tangency, a. Determine the distance along the tangent at the end point of the spiral. b. What is the maximum velocity that a

The back tangent AV of a simple curve has an azimuth of 252° while that of its forward tangent VB has an azimuth of 300°. The degree of the simple curve is 4º, arc basis. It is desired to replace the simple curve with another curve having 100 m spirals at its end. Without changing the points of tangency, a. Determine the distance along the tangent at the end point of the spiral. b. What is the maximum velocity that a

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

N S Curves W E В Problem: U Three curves are to be connected. Data are obtained in the field as follows: R Line AB has a bearing of N 60° E Line BC has a bearing of S 60° E V T1 = 250.00 m R2 = 250.00 m I2 = 70° Tangent CD is parallel with tangent FG T2 R1 Y a. Determine R1 and R3. O2 R2 b. Determine T, and T3. I1 c. Determine C1, C2 and C3. d. Determine L1, L2 and L3. e. If the stationing of A is at N 120 + 340.14 m, determine the stationing of C, E and G. Оз 13 T3 F R3 G.
what is the curvature of the curve x^2 - 4y = 0 when x = 8.3
2. Determine the orthogonal trajectory of the family of hyperbolas y? – 121x? = c. Sketch some of the curves.
Find the radius of curvature of the curve x +y³ = 4xy at (2, 2). 0.3536 O 0.6353 O 0.3365 O 0.5336
The angle of intersection of T.S and S.T is 70 degrees. The radius of the circular curve is 260 m and the spiral curve length is 110 m. Determine the element of the spiral curve. a. Determine the external distance of the curve. b. Determine the central angle of the circular curve. c. Determine the deflection angle at the end point of the spiral. d. Determine the offset from tangent at the endpoint of the spiral. e. Determine the distance along the tangent at the midpoint of the spiral.
Sta. PT of a compound curve is at 15 + 480. I¡ = 30°, l2 = 36°, D1 = 4°, D2 = 5°. a. What is the sta. of the vertex of the compound curve? b. Determine the long chord of the compound curve.
1. What is the stationing of PC if the stationing of PI = 042+089.6 based on the given elements of the compound curve as follows: I1=180 ,I2 =23.50 ;D1=20 , D2=40 Show your solution
The elements of the compound curve are as follows: (use arc basis) 11 = 18° 12 = 23.5° If the stationing of PI = 42+089.6, 6. Determine the length of Radius 2. 7. Determine the length of tangent 1. 8. Determine the stationing of the PC. 9. Determine the stationing of PT. D1 = 2° D2 = 4°
• Determine the location of PC and PT. • Calculate the dimensions of the parts of our simple curve (use 20m arc). • I, R, T, L, E, M, LC e = 120° (PI = 2020 m /PT D= 3.5°
The elements of a compound curve are as follows: 11 = 18 12 = 23.5 D1 = 2 D2 = 4 If STA PT = 42+205.88, determine STA PI. *
S Curves V Problem: 1+12 For the given compound curve (see figure): a. Determine R, and R2. b. Determine T, and T2. c. Determine C, and C2. V d. Determine L, and L2. e. If the stationing of PC is at 10 + 304.62 m, determine the stationing of PCC and PT. T, +T2 РСС 12 = 15° PI, I = 12° Pl2 T1 T2 Y C1 PCO (Sta PC = 10 +304.62) PT Long chord 300m 12 = 15° R2 R, 02 I = 12°
Find the equation of the curve whose slope at any point (x, y) is given and which passes through the specified point. 12. slope is x Vỹ ; through (1, 9)