The ascorbic acid, C6H806 (176.124 g/mmol) content of a bottle of peach juice containing 2.50 L was determined by titration with a standard solution of potassium iodate, KIO3. The KIO3 solution was prepared by dissolving 100.4 mg primary standard grade KIO3 (214.001 mg/mmol) to a final volume of 250.0 mL. To a 200.00-mL aliquot of the sample, 10 mL of KI, 10 mL of HCI and 5 mL of starch solution were added and subsequently titrated, requiring 18.19 mL of the KIO3 titrant. The relevant reactions are given below: KIO3 + 5KI + 6H*→ 312 + 6K+ + 3H₂O C6H8O6 + 12 C6H6O6 +21+ 2H+

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter4: Reactions In Aqueous Solution
Section: Chapter Questions
Problem 53QAP: The molarity of iodine in solution can be determined by titration with arsenious acid, H3AsO4. The...
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The ascorbic acid, C6H806 (176.124 g/mmol) content of a bottle of peach juice containing 2.50 L was
determined by titration with a standard solution of potassium iodate, KIO3. The KIO3 solution was
prepared by dissolving 100.4 mg primary standard grade KIO3 (214.001 mg/mmol) to a final volume of
250.0 mL. To a 200.00-mL aliquot of the sample, 10 mL of KI, 10 mL of HCI and 5 mL of starch solution
were added and subsequently titrated, requiring 18.19 mL of the KIO3 titrant. The relevant reactions are
given below:
KIO3 + 5KI + 6H*→ 312 + 6K+ + 3H₂O
C6H8O6 + 12 C6H606+21+ 2H+
1. What is the molarity of the KIO3 solution?
a. 0.005701 M
b.
0.002346 M
C.
0.001877 M
d. 0.004692 M
2. How many millimoles of ascorbic acid is in the titrated sample?
a.
0.1280 mmol
b. 0.1024 mmol
C.
0.2560 mmol
d.
0.1126 mmol
3. What is the mass of ascorbic acid per bottle of the peach juice?
a.
273.9 mg
b.
200.4 mg
C.
225.5 mg
d. 250.5 mg
Transcribed Image Text:The ascorbic acid, C6H806 (176.124 g/mmol) content of a bottle of peach juice containing 2.50 L was determined by titration with a standard solution of potassium iodate, KIO3. The KIO3 solution was prepared by dissolving 100.4 mg primary standard grade KIO3 (214.001 mg/mmol) to a final volume of 250.0 mL. To a 200.00-mL aliquot of the sample, 10 mL of KI, 10 mL of HCI and 5 mL of starch solution were added and subsequently titrated, requiring 18.19 mL of the KIO3 titrant. The relevant reactions are given below: KIO3 + 5KI + 6H*→ 312 + 6K+ + 3H₂O C6H8O6 + 12 C6H606+21+ 2H+ 1. What is the molarity of the KIO3 solution? a. 0.005701 M b. 0.002346 M C. 0.001877 M d. 0.004692 M 2. How many millimoles of ascorbic acid is in the titrated sample? a. 0.1280 mmol b. 0.1024 mmol C. 0.2560 mmol d. 0.1126 mmol 3. What is the mass of ascorbic acid per bottle of the peach juice? a. 273.9 mg b. 200.4 mg C. 225.5 mg d. 250.5 mg
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