The alcohol content of a certain low alcohol beer was determined using volumetric analysis. In this analysis, a 17.1-mL sample of the beer was pipetted into a 100-mL volumetric flask and the solution was made up to the mark. Then 20.4 mL aliquots of his solution were titrated against acidified potassium dichromate solution, K,Cr,0, of concentration 0.077 mol/L. A mean titre (or volume of the titrant) of 19.9 mL was obtained. The equation for the analysis is: 2- 3+ 2 Cr,0, (aq) + 3 C,H,OH (aq) + 16 H (aq) = 4 Cr (aq) + 3 CH,COOH (aq) + 11 H,0 (I) What was the molarity of the alcohol in the beer?

Principles of Modern Chemistry
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ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter17: Electrochemistry
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The alcohol content of a certain low alcohol beer was
determined using volumetric analysis. In this analysis, a
17.1-mL sample of the beer was pipetted into a 100-mL
volumetric flask and the solution was made up to the
mark. Then 20.4 mL aliquots of his solution were titrated
against acidified potassium dichromate solution, K,Cr,0,
of concentration 0.077 mol/L. A mean titre (or volume of
the titrant) of 19.9 mL was obtained. The equation for the
analysis is:
2-
3+
2 Cr,0," (aq) + 3 C,H,OH (aq) + 16 H (aq) = 4 Cr
(aq) + 3 CH,COOH (aq) + 11 H,0 (I)
What was the molarity of the alcohol in the beer?
Transcribed Image Text:The alcohol content of a certain low alcohol beer was determined using volumetric analysis. In this analysis, a 17.1-mL sample of the beer was pipetted into a 100-mL volumetric flask and the solution was made up to the mark. Then 20.4 mL aliquots of his solution were titrated against acidified potassium dichromate solution, K,Cr,0, of concentration 0.077 mol/L. A mean titre (or volume of the titrant) of 19.9 mL was obtained. The equation for the analysis is: 2- 3+ 2 Cr,0," (aq) + 3 C,H,OH (aq) + 16 H (aq) = 4 Cr (aq) + 3 CH,COOH (aq) + 11 H,0 (I) What was the molarity of the alcohol in the beer?
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