Suppose, you have been given a non-negative integer which is the height of a ‘house of cards’. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a ‘house of cards’ of specific height given by the parameter.

Suppose, you have been given a non-negative integer which is the height of a ‘house of cards’. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a ‘house of cards’ of specific height given by the parameter.

Operations Research : Applications and Algorithms

4th Edition

ISBN:9780534380588

Author:Wayne L. Winston

Publisher:Wayne L. Winston

Chapter17: Markov Chains

Section: Chapter Questions

Problem 12RP

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Suppose, you have been given a non-negative integer which is the height of a ‘house of cards’. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a ‘house of cards’ of specific height given by the parameter. there is a picture given in that section. public int hocBuilder (int height){ // TO DO } OR def hocBuilder(height): #TO DO
Suppose, you have been given a non-negative integer which is the height of a ‘house ofcards’. To build such a house you at-least require 8 cards. To increase the level (or height)of that house, you would require four sides and a base for each level. Therefore, for the toplevel, you would require 8 cards and for each of the rest of the levels below you wouldrequire 5 extra cards. If you were asked to build level one only, you would require just 8cards. Of course, the input can be zero; in that case, you do not build a house at all.Complete the recursive method below to calculate the number of cards required to builda ‘house of cards’ of specific height given by the parameter.
You are playing a card game. In this game, your opponent places n monster cards onto the board, the i th of which has hi health points. You in turn have m ≥ n hero cards in your hand, the j th of which deals dj damage per turn. To begin the game, you will choose n heroes from your hand and assign each of them to a different enemy monster. Each turn, your heroes will deal damage equal to their damage power to the opposing enemy. If at any point an opponent’s monster reaches 0 health or less, then it is destroyed. You are given a limited number of turns k to destroy all enemy monsters. Design an algorithm which runs in O(m + n log n) time and determines whether it is possible to assign your heroes in such a way as to destroy all enemy monsters in k turns or fewer First develop a Θ(m log m) time algorithm, then improve it to Θ(m + n log n) Do not write the code, give steps and methods. Explain the steps of algorithm, and the logic behind these steps in plain English input is The number of…
Suppose, you have been given a non-negative integer which is the height of a 'house of cards'. To build such a house you at-least require 8 cards. To increase the level (or height) of that house, you would require four sides and a base for each level. Therefore, for the top level, you would require 8 cards and for each of the rest of the levels below you would require 5 extra cards. If you were asked to build level one only, you would require just 8 cards. Of course, the input can be zero; in that case, you do not build a house at all. Complete the recursive method below to calculate the number of cards required to build a 'house of cards' of specific height given by the parameter. Height 1 Height 2 Height 3 public int hocBuilder (int height) { // TO DO } OR def hocBuilder (height): #то DO
In a card game, your opponent places n monster cards onto the board, the i th of which has hi health points. You in turn have m ≥ n hero cards in your hand, the j th of which deals dj damage per turn. To begin the game, you will choose n heroes from your hand and assign each of them to a different enemy monster. Each turn, your heroes will deal damage equal to their damage power to the opposing enemy. If at any point an opponent’s monster reaches 0 health or less, then it is destroyed. You are given a limited number of turns k to destroy all enemy monsters. Design an algorithm which runs in O(m + n log n) time and determines whether it is possible to assign your heroes in such a way as to destroy all enemy monsters in k turns or fewer First develop a Θ(m log m) time algorithm, then improve it to Θ(m + n log n) Do not write the code, give steps and methods. Explain the steps of algorithm, and the logic behind these steps in plain English input is The number of monsters n, the health…
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In an astronomy board game, N planets in an imaginary universe do not follow the normal law of gravitation. All the planets are positioned in a row. The planetary system can be in a stable state only if the sum of the mass of all planets at even positions is equal to the sum of the mass of planets at the odd positions. Initially, the system is not stable, but a player can destroy one planet to make it stable. Find the planet that should be destroyed to make the system stable. If no such planet exists, then return -1. If there are multiple such planets, then destroy the planet with the smallest index and return the index of the destroyed planet. Example Let N-5 and planets = [2,4,6,3,4]. Destroying the fourth planet of mass 3 will result in planets = [2,4,6,4], and here, the sum of odd positioned planets is (2+6)=8, and the sum of even positioned planets is (4+4)=8, and both are equal now. Hence, we destroy the fourth planet. 11 MNBASK19922 13 14 15 16 17 18 20 * The function is…
You are playing the popular card game “Inscribings”. In this game, your opponent places n monster cards onto the board, the ith of which has hi health points. You in turn have m ≥ n hero cards in your hand, the jth of which deals dj damage per turn. To begin the game, you will choose n heroes from your hand and assign each of them to a different enemy monster. Each turn, your heroes will deal damage equal to their damage power to the opposing enemy. If at any point an opponent’s monster reaches 0 health or less, then it is destroyed. You are given a limited number of turns k to destroy all enemy monsters. Design an algorithm which runs in O(m + n log n) time and determines whether it is possible to assign your heroes in such a way as to destroy all enemy monsters in k turns or fewer. If it is possible, your algorithm must also return any such assignment. Need an algorithm which runs in Θ(m log m) time.
Consider a game that you want to develop to impress your friend. You design a game with rules: “A player rolls a die and a coin in a single throw. Each die has six faces. These faces contain 1, 2, 3, 4, 5, and 6 spots. A coin has two faces, e.g., Head and Tail (Head is considered as 1 and Tail as 0). After the die and coin have come to rest, the sum of the upward spots of die and coin is calculated. If the sum is 7 (makes 6 for the die and Head for coin) the player wins, if the sum is 1 (makes 1 for the die and Tail for coin) the player loses. The remaining point becomes the player's “point”. To win the game, the player must continue rolling the die and coin until the player makes his "point". The player loses by getting 7 or 1 before making his point.” Write down a Java program that simulates this game.
Correct answer will be upvoted else Multiple Downvoted. Computer science. player begins the game from the 1-st stage and should beat the stages in expanding request of the stage number. The player dominates the match in the wake of beating the n-th stage. There is all things considered one designated spot on each stage, and there is consistently a designated spot on the 1-st stage. Toward the start of the game, just the designated spot on the 1-st stage is initiated, and any remaining designated spots are deactivated. At the point when the player gets to the I-th stage that has a designated spot, that designated spot is initiated. For each attempt of a phase, the player can either beat the stage or bomb the stage. On the off chance that they beat the I-th stage, the player is moved to the i+1-st stage. On the off chance that they bomb the I-th stage, the player is moved to the latest designated spot they actuated, and they need to beat the stages after that designated spot once…
Pedro has a collection of 100 rocks. At the beginning of each day, he collects all the rocks into a single collection. Then he then divides the rocks into two smaller collections, one with a rocks and one with b rocks (so a+b= 100), and he writes down ab (the product of their sizes) on a card. Then he goes to one of the his two collections and divides it into two smaller collections, one with c rocks and one with d rocks, and writes down the product cd of their sizes on the card. So now Pedro has three collections. He now goes to one of the collections and divides it into two smaller collections of sizes e and ƒ and writes ef on the card. He continues in this way until he is forced to stop because he has 100 collections with 1 rock each. At this point he has written down 99 numbers on his card. He adds up the numbers and calls this number the score for the day. Pedro repeats this experiment each day, but can make different decisions about how to divide collec- tions. For example, maybe…
There are four people who want to cross a rickety bridge; they all begin on the same side. You have 17 minutes to get them all across to the other side. It is night, and they have one flashlight. A maximum of two people can cross the bridge at one time. Any party that crosses, either one or two people, must have the flashlight with them. The flashlight must be walked back and forth; it cannot be thrown, for example. Person 1 takes 1 minute to cross the bridge, person 2 takes 2 minutes, person 3 takes 5 minutes, and person 4 takes 10 minutes. A pair must walk together at the rate of the slower person's pace. Write the specification of an algorithm that solves the problem.