Sulphuric acid (H2SO4) has a PKa of -3. a) Write an equation showing how sulphuric acid can act as an acid. b) Calculate the Ka of the equilibrium you have written in part a), given that sulphuric acid has a PKa of -3

Sulphuric acid (H2SO4) has a PKa of -3. a) Write an equation showing how sulphuric acid can act as an acid. b) Calculate the Ka of the equilibrium you have written in part a), given that sulphuric acid has a PKa of -3

Chemistry & Chemical Reactivity

10th Edition

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases

Section16.10: The Lewis Concept Of Acids And Bases

Problem 2.3ACP

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Question

Sulphuric acid (H2SO4) has a PKa of -3.
a) Write an equation showing how sulphuric acid can act as an acid.
b) Calculate the Ka of the equilibrium you have written in part a), given that
sulphuric acid has a PKa of -3

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Sulphuric acid (H2SO4) has a PKa of -3. a) Write an equation showing how sulphuric acid can act as an acid . b) Calculate the Ka of the equilibrium you have written in part a), given that sulphuric acid has a PKa of -3. c) Explain whether sulphuric acid is a strong acid or a weak acid 1: HA > H* + A- d) A solution of an unknown acid has a Pka of 4.4. Calculate the concentration of the undissociated molecules (HA) if a solution of this acid has a pH of 3.2 (Assume that the concentration of H* ions and A ions are equal). .