The FBD of the block should have looked like this.1. Drag and drop the heads and tails of the vectorsto construct the free-body diagram.2. Note that angles do not need to be exact andmagnitudes are not considered.ffric; 180°N; 90°mg; 271°F: 335°1.A contestant in a winter sporting event pushes a block of ice of mass m across a frozen lake asshown in the figure. The coefficient of static friction between the block and ice is µs, and thecoefficient of kinetic friction is µk. is the angle the force makes with the x-axis.In this part, we are going to set-up Newton's second Law equations for the cases(1) when the ice block just starts moving, and(2) when it is accelerating to the right with an acceleration a.All answers are symbolic. ALL ANSWERS ARE CASE-SENSITIVE.0AY Subpart 1: Newton's Second Law along the y-axis(i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking intoaccount their signs (forces pointing upwards are positive and downward are negative) in terms of thenormal force N, weight mg, F and 8.In both scenarios, there is no acceleration along the y-direction, therefore, a, = 0.ΣF,= -Fsin0+N-mgy(ii) Using (1) to sol for N.N = mg + Fsin(25°)✔= may = 0 (1)Think: In (2) is N greater than the weight, less than the weight or equal to the weight?(2)Subpart 2: Set up Newton's Second Law in the x-direction when the ice block is stationary.(i) Write Newton's Second Law along the x-axis by adding all forces in the x-direction taking intoaccountr their signs (forces pointing to the right are positive and pointing to the left are negative)when the block is not moving in terms of F, 0, and the force of static friction f.DON'T forget the subscript on fg.If the block is not moving, then ax = 0.ΣF=Ο μενMk N(ii) What value of static friction should you use just before the block starts moving?fs.max=X√ = max = 0 (3)Subpart 3: Set up Newton's Second Law in the x-direction when the ice block is accelerating to

Name: The FBD of the block should have looked like this.1. Drag and drop th
Uploaded: 2024-03-20T06:56:46.000Z
Channel: Bartleby
Description: The FBD of the block should have looked like this.1. Drag and drop the heads and tails of the vectorsto construct the free-body diagram.2. Note that angles do not need to be exact andmagnitudes are not considered.ffric; 180°N; 90°mg; 271°F: 335°1.A