Subject : Data structure and algorithms Goal of the work : Consolidating knowledge on the theoretical foundations of abstract data structures, mastering the skills of calculating the declared amount of memory for structures using C++ syntax. Task : Given a data structure with three fields: an array of integers, a matrix of real numbers, and a string of characters. Calculate the total memory size (in bits, bytes, kilobytes, and megabytes) for record A, table B, and dynamic array variables C. *note: The data types are respectively equal to the memory size "short-2 byte", "int-4", "long-8", "float-4", "double-8", "long double -12", " char-1".
Subject : Data structure and algorithms Goal of the work : Consolidating knowledge on the theoretical foundations of abstract data structures, mastering the skills of calculating the declared amount of memory for structures using C++ syntax. Task : Given a data structure with three fields: an array of integers, a matrix of real numbers, and a string of characters. Calculate the total memory size (in bits, bytes, kilobytes, and megabytes) for record A, table B, and dynamic array variables C. *note: The data types are respectively equal to the memory size "short-2 byte", "int-4", "long-8", "float-4", "double-8", "long double -12", " char-1".
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Subject : Data structure and algorithms
Goal of the work : Consolidating knowledge on the theoretical foundations of abstract data structures, mastering the skills of calculating the declared amount of memory for structures using C++ syntax.
Task : Given a data structure with three fields: an array of integers, a matrix of real numbers, and a string of characters. Calculate the total memory size (in bits, bytes, kilobytes, and megabytes) for record A, table B, and dynamic array variables C.
*note: The data types are respectively equal to the memory size "short-2 byte", "int-4", "long-8", "float-4", "double-8", "long double -12", " char-1".
![TASK-ASSIGNMENT
struct DATA
{
short P1[25];
double P2[7][7];
char P3[78];
} A, B[73],*C;
C=new DATA (21);](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faccb78b0-37ca-42b4-9fac-cee8b2a7f604%2F38090ec2-2bdd-4274-aa46-d16bd09138ea%2F2ic6c9m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:TASK-ASSIGNMENT
struct DATA
{
short P1[25];
double P2[7][7];
char P3[78];
} A, B[73],*C;
C=new DATA (21);
![struct DATA
{
short P1[24]
long double P2[8][7];
char P3[51]
} A, B[50], C
C = new DATA (20)
Vp1 = 2b * 24 = 48b
Vp2 = 12b * 8 * 7 = 672 b
Vp3 = 1b * 51 = 51b
VaVp1 + Vp2 + Vp3 = 48 +672 +51 = 771 b
Vb =
771 5038550 b
Vc = 4 + 771 * 20 = 15424 b
Vgeneral = Va + Vb + Vc = 771 +38550 + 15424 = 54745 b
1 b = equal to 8 bits
54745*8 = 437960 bit
54745/ 1024 = 53,46 kb
53,46 / 1024 = 0,052 mb
EXAMPLE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faccb78b0-37ca-42b4-9fac-cee8b2a7f604%2F38090ec2-2bdd-4274-aa46-d16bd09138ea%2Fnxaq7dp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:struct DATA
{
short P1[24]
long double P2[8][7];
char P3[51]
} A, B[50], C
C = new DATA (20)
Vp1 = 2b * 24 = 48b
Vp2 = 12b * 8 * 7 = 672 b
Vp3 = 1b * 51 = 51b
VaVp1 + Vp2 + Vp3 = 48 +672 +51 = 771 b
Vb =
771 5038550 b
Vc = 4 + 771 * 20 = 15424 b
Vgeneral = Va + Vb + Vc = 771 +38550 + 15424 = 54745 b
1 b = equal to 8 bits
54745*8 = 437960 bit
54745/ 1024 = 53,46 kb
53,46 / 1024 = 0,052 mb
EXAMPLE
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