Subject 15 is an outlier in the y direction. Subject 18 is an outlier in the x direction. The correlation for all 18 subjects is , for all except Subject 15 is except Subject 18 is , and for all Round your answers to 3 decimals.
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- A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage x¯1x¯1 = $ 1,101 x¯2x¯2 = $ 1,766 Sample Standard Deviation s1 = $ 696 s2 = $ 838 Repair Incidents n1 = 12 n2 = 9 (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round answers to 3 decimal places. Negative values should be indicated by a minus sign.) (b) Repeat part (a), using the assumption of unequal variances with Welch's formula for d.f. (Round answers to 2 decimal places. Negative values should be indicated by a minus sign.) (d) Construct separate…A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,153 X¯¯¯2X¯2 = $ 1,751 Sample Std. Dev. s1 = $ 663 s2 = $ 820 Repair Incidents n1 = 16 n2 = 14 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 99 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 99% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…A patient screens positive for Disease Y. The screener has a sensitivity of 60%. The best next step for the patient is most likely: Start treatment for Disease Y Get a diagnostic test Take a different screening test None of these are correct.
- A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,077 X¯¯¯2X¯2 = $ 1,800 Sample Std. Dev. s1 = $ 693 s2 = $ 814 Repair Incidents n1 = 16 n2 = 13 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 90% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…x1: Rate of hay fever per 1000 population for people under 25 96, 92, 122,126, 94, 123,12, 93, 125, 95, 125, 117, 97, 122,127, 88 x2: Rate of hay fever per 1000 population for people over 5097, 112,103, 96,114, 88, 110, 79, 15, 100, 89, 114, 85, 96 x1 = s1 = x2 = s2 = Compute the corresponding z or t-value as appropriate. (Test the difference ?1 − ?2. Do not use rounded values. Round your answer to three decimal places.) What is the value of the sample test statistic? Find a 90% confidence interval for ?1 − ?2. (Round your answers to two decimal places.)lower limit:________upper limit:________Blood pressure Diastolic blood pressure in adults is normally |distributed with µ = 80 mm Hg and o = 12 mm Hg. In a ran- dom sample of 300 adults, how many would be expected to have a diastolic blood pressure below 70 mm Hg?
- Total plasma volume by the overall health and physical activity of an individual. Suppose that a random sample of 40 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that o = 7.10 ml/kg for the distribution of blood plasma. is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced When finding an 99% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) z. = (a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) n is large the distribution of volumes is normal o is unknown the distribution of volumes is…Price_($000)/Sq Ft 1/Sq Ft Location 14.0542 0.0653 0 17.2907 0.0524 0 18.3029 0.00649 0 15.7341 0.04374 0 14.8521 0.01913 0 15.3572 0.0197 0 18.3278 0.01583 0 15.8483 0.41563 0 17.392 0.29976 0 15.8826 0.1798 0 15.5492 0.00816 0 14.619 0.0325 0 15.7633 0.21829 0 15.1289 0.015939 0 17.2874 0.18765 0 15.6938 0.00986 0 15.3672 0.03096 0 15.3126 0.01917 0 17.4008 0.06055 0 16.1066 0.0611 0 16.6637 0.1171 1 16.5504 0.05552 1 17.0575 0.00657 1 17.9466 0.1407 1 17.8913 0.0648 1 15.5396 0.03339 1 18.6629 0.03443 1 18.0774 0.019 1 20.8122 0.20162 1 18.3237 0.319 125/8 -17/8. over. 23/10-13/10
- QuestionA random sample of 25 tires gave the average life as 38000 km and S.D. as 5000 km. Can it be concluded that the sample isdrawn from a population with a mean life of 40000 km?Obtained vaule from community is -1.49 and the critical vaule of the state is 1.96. Compare the obtained vaule to the critical vaule to see if the average number of cases in the community is different from that of the state.What proportion of male growth plates fuse between 16 and 17 years of age? The proportion of male growth plates that fuse between 16 and 17 years of age i
