Study the code below: public __________ ____________() { MyLinkedList newlist = new MyLinkedList<>(); for(Node ptr=head;ptr!=null;ptr=ptr.next) { newlist.prepend(ptr.element); } return newlist; } What is the purpose of the code
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A: The program given is the required method is added and highlighted. You can put your code there.
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- Create a node class named LinkedNodes that uses up to 4 dynamic pointers to connect it to the other 8 nodes in the structure (a total of 9). The data in each node will be a unique integer number from 1 through 9. Include in your class definition these functions at a minimum: getVal(), setVal(), getNext(), setNext(), getPrev(), setPrev(), constructor(s) and destructor. Write a simple program to load these nodes into a linked structure. Do not use an array, the pointers will do that for you. You should be able to reach any node from any other node in the structure by traversing a maximum of 2 nodes from the current one. The output from your program should report the traversals between all nodes in the structure, starting with the node whose value is one. (See the example below) Node 1 2 3 4 5 6 7 8 9 -> Traverses to Node 1 Node 2 1->2 2->6->1 3->6->1 3->7->2 4->6->1 4->7->2 4->8->3 5->6->1 5->7->2 5->8->3 6->1->2 6->1->3 7->1->3 8->3 6->1 7->1 8->1 9->1 Node 3 1->3 2->3 7->2 8->2 9->2…Having trouble with creating the InsertAtEnd function in the ItemNode.h file below. " // TODO: Define InsertAtEnd() function that inserts a node // to the end of the linked list" Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts ------------------------------------------------------- main.cpp -------------------------------------------------------- #include "ItemNode.h" int main() { ItemNode *headNode; // Create intNode objects ItemNode *currNode; ItemNode *lastNode; string item; int i; int input; // Front of nodes list headNode = new ItemNode(); lastNode = headNode; cin >> input; for (i = 0; i < input; i++) { cin >> item;…In this assignment, you will create a Linked List data structure variant called a “Circular Linked List”. The Node structure is the same as discussed in the slides and defined as follows (we will use integers for data elements): public class Node { public int data; public Node next; } For the Circular Linked List, its class definition is as follows: public class CircularLinkedList { public int currentSize; public Node current; } In this Circular Linked List (CLL), each node has a reference to an existing next node. When Node elements are added to the CLL, the structure looks like a standard linked list with the last node’s next pointer always pointing to the first. In this way, there is no Node with a “next” pointer in the CLL that is ever pointing to null. For example, if a CLL has elements “5”, “3” and “4” and “current” is pointing to “3”, the CLL should look like: Key observations with this structure: The currentSize is 3 meaning there…
- class Node: def __init__(self, e, n): self.element = e self.next = n class LinkedList: def __init__(self, a): # Design the constructor based on data type of a. If 'a' is built in python list then # Creates a linked list using the values from the given array. head will refer # to the Node that contains the element from a[0] # Else Sets the value of head. head will refer # to the given LinkedList # Hint: Use the type() function to determine the data type of a self.head = None # To Do # Count the number of nodes in the list def countNode(self): # To Do # Print elements in the list def printList(self): # To Do # returns the reference of the Node at the given index. For invalid index return None. def nodeAt(self, idx): # To Do//give the output of the following program and draw the link list. struct node{ int info; struct node *link;};typedef struct node *nodePTR;void insort(nodePTR*,struct Info);nodePTR getnode();int main(void){nodePTR p=NULL,head=NULL,save;inti; for(i=0;i<3;i++){ insort (&head,i+5);}save=head;do{ printf("%d",save->info); save=save->link;}while(save!=NULL); return0;}nodePTR getnode(){nodePTR q;q=(nodePTR)malloc(sizeof(struct node));return q;}void insort(NODEPTR *head , int x){ NODEPTR p,q,r; q=NULL; for(p=*head; p!=NULL &&x>p->info; p=p->link) q=p; if(q=NULL) { p=getnode(); p->info=x; p->link=head; head=p; }else{ r=getnode(); q->link=r; r->info=x; r->link=p; }}code: public class PasswordGeneratorAndStorage {/*** Adds an application to the applications ArrayList. If index is -1, add application* to the end of applications. Else is index is within the size of applications, add* application at that index in applications. Otherwise, return. However, if applications * or application is null, return.* * @param applications* @param application* @param index*/public static void addApplication(ArrayList<String> applications, String application, int index) {// TODO: FILL IN BODY}/*** Generates a random password of length passwordLength and adds it to the end of* passwords if index is -1, or adds it to the index of passwords if index is within the* size of passwords (similar to how the addApplication adds an application). To generate* the random password, use rand to generate a random int within the size of characters. You* can then use this int to grab the char at that index in characters and concatenate that* to your String password variable.…
- ion C Lons Employee -id: int -name String - dob : Date -staff : ArrayList +setid(int): void +getld() : int +setName(String): void +setDob(Date) : void +getDob(): Date +addStaff(Employee) : void +getStaff() : ArrayList#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;}; bool DelOddCopEven(Node* headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif // definition of DelOddCopEven of Assignment 5 Part 1//Algorithm should: /*NOT destroy any of the originally even-valued node. This means that the originally even-valued nodes should be retained as part of the resulting list. Destroy…What criteria should be used to evaluate an ArrayList's performance?
- Parking (car Cars[], car Park[], int Area) { Car Cr, int CrNb; CrNb <-- 0; Park <-- { }; Cr <-- Select (Cars) I/ Cr = / if the Cars = {} while (Feasible (Cr)) do { Remove (Cr, Cars); Add (Cr, Park); CrNb <-- CrNb +1; Cr <-- Select (Cars) } if exist-Solution (Park) Then Success else return Error } Trace the above Greedy algorithm with the following data: Area = 1000, Cars [100, 50, 90, 70. 200, 300, 400, 80, 200] the cost for each parked car is 3JD. The objective function is: %3D k Max (ΣCis 1000) K |=1#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;};void DelOddCopEven(Node*& headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif6. Suppose that we have defined a singly linked list class that contains a list of unique integers in ascending order. Create a method that merges the integers into a new list. Note the additional requirements listed below. Notes: ● . Neither this list nor other list should change. The input lists will contain id's in sorted order. However, they may contain duplicate values. For example, other list might contain id's . You should not create duplicate id's in the list. Important: this list may contain duplicate id's, and other list may also contain duplicate id's. You must ensure that the resulting list does not contain duplicates, even if the input lists do contain duplicates.