Solve the structure of this compound by looking at the 1H, 13C NMR data provided. You must fill all of the parts to this question in the given spaces. Molecular formula: C6H14N2O2 5Solvent: D₂OField: 500 MHz (¹H): 125 MHz (13C)1H4.0DEPT 13513C170(1)3.81603.6Solution of problem # 3:Degree of unsaturation:13C NMR interpretation:DEPT interpretation:150Peak A (3.75 ppm)Peak D (1.72 ppm)3.414053.21303.01202.811020¹H (ppm)100UC (ppm)24Peak B (3.01 ppm)902.260October2.070Peak E (1.56 ppm)Structure of unknown compoundملة(2)i1.8(2)601650'H NMR interpretation (I want a picture of the fragment that you can determine from the shift andsplitting):(2)1.44030Peak C (1.90 ppm)1.2

Given compound: C6H14N2O2 To Solve the structure of this compound by looking at the 1H, 13C NMR data…

Answered: Solve the structure of this compound by…

Solve the structure of this compound by looking at the 1H, 13C NMR data provided. You must fill all of the parts to this question in the given spaces. Molecular formula: C6H14N2O2

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter9: Atomic Absorption And Atomic Fluorescence Spectrometry

Section: Chapter Questions

Problem 9.8QAP

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

Solve the structure of this compound by looking at the ¹H, ¹³C NMR data provided. You must fill all of the parts to this question in the given spaces. Molecular formula: C₆H₁₄N₂O₂

5
Solvent: D₂O
Field: 500 MHz (¹H): 125 MHz (13C)
1H
4.0
DEPT 135
13C
170
(1)
3.8
160
3.6
Solution of problem # 3:
Degree of unsaturation:
13C NMR interpretation:
DEPT interpretation:
150
Peak A (3.75 ppm)
Peak D (1.72 ppm)
3.4
140
5
3.2
130
3.0
120
2.8
110
20
¹H (ppm)
100
UC (ppm)
24
Peak B (3.01 ppm)
90
2.2
60
October
2.0
70
Peak E (1.56 ppm)
Structure of unknown compound
ملة
(2)
i
1.8
(2)
60
16
50
'H NMR interpretation (I want a picture of the fragment that you can determine from the shift and
splitting):
(2)
1.4
40
30
Peak C (1.90 ppm)
1.2

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