Solution A was prepared by weighing 6.08 grams of K3Fe(CN)6 (MW 329.2 g/mol) and dissolving the solid with distilled water until the 1000-mL mark of the volumetric flask. A 26.5 mL aliquot of solution A was transferred to a new 250.00 mL volumetric flask. Distilled water is added until the 250.00 mL mark to give solution B. Calculate the concentration of K3Fe(CN)6 in solution B. Express your answers in 4 SIGNIFICANT FIGURES.

Introductory Chemistry For Today
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Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.107E
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Solution A was prepared by weighing 6.08 grams of K3Fe(CN)6 (MW 329.2 g/mol) and dissolving the solid with distilled
water until the 1000-mL mark of the volumetric flask. A 26.5 mL aliquot of solution A was transferred to a new 250.00 mL
volumetric flask. Distilled water is added until the 250.00 mL mark to give solution B. Calculate the concentration of
K3Fe(CN)6 in solution B. Express your answers in 4 SIGNIFICANT FIGURES.
Transcribed Image Text:Solution A was prepared by weighing 6.08 grams of K3Fe(CN)6 (MW 329.2 g/mol) and dissolving the solid with distilled water until the 1000-mL mark of the volumetric flask. A 26.5 mL aliquot of solution A was transferred to a new 250.00 mL volumetric flask. Distilled water is added until the 250.00 mL mark to give solution B. Calculate the concentration of K3Fe(CN)6 in solution B. Express your answers in 4 SIGNIFICANT FIGURES.
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