So if i had page size 8k (which is 2^13=8k) & had a virtual address length of 32 bits and did 32 - 13 = 19, is that the vpn or offset? <<<<<<< please tell which
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So if i had page size 8k (which is 2^13=8k) & had a virtual address length of 32 bits and did 32 - 13 = 19, is that the vpn or offset? <<<<<<< please tell which
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- Assuming a 2-KB (2048 bytes) page size, what is the page number for byte address 7353187? Select one: О а. 3590 O b. 3590.4 О с. 867 O d. 735 In a demand-paging system, assuming main memory access time = 10 nanoseconds and page-fault service time = 3 milliseconds, what is the EAT(effective access time) of the system given a page fault rate of o.01%? Select one: O A. 130 nanoseconds O B. 310 nanoseconds O C. 400 nanoseconds O D. 3100 nanosecondsSuppose we have a computer system with 44-bit logical addresses, page size of 64KiB, and 4 bytes per page table entry. b. Suppose we use two-level paging and arrange for all page tables to fit into a single page frame. How will the bits of the address be divided up? (show your work) c. Suppose we have a program with a 4GiB address space. Counting the program and all page tables, using the two-level page table scheme from the previous question, how much memory, in number of page frames, is used? (show your work)Consider a process of 200 KB which has 2 segments each segment size is 256 KB. Which of the following is the correct number of bytes of overhead in segmented paging if the page table entry is 4B, the segment table entry is 2B and Page size is 2KB.
- Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. 8 bits are used for offset, 8 bits are used for page # and the max number of pages a process can have is 256. e. Translate the following virtual addresses to physical addresses, and show how you obtain the answers. (Hint: You do not need to convert hexadecimal numbers to decimal ones.) 0x0389 0xDF78 0x0245 0x8012 f) Now, suppose that the OS uses a two-level page table. Draw the page table. (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) g)What is the size of the two-level page table…Convert the physical addresses to logical using the combined paging segmentation scheme Logical Address (Seg#, Page#, offset) 256 Physical Address 544 850 ? 2 672 1588 736 1630 ? 500 ? 1248 600 ? 1504 4 1632 1792 Hint: phy, add.= base_address + (page# x page_size) + offset **You must also explain how you computed your answer. Shows details of solution. 3.A computer system with 32 bit word length is implementing paging with 14 bit logical addresses and 4KB pages. If physical memory size is 64K Bytes, mark all correct statements below: O In logical addresses , p is 4 bits long. O In physical addresses , f is 6 bits long. O Logical memory size is at most 32 pages per program. O In logical addresses , d is 10 bits long. O Physical memory has 16 frames. O Frame size is 4K words. O In physical addresses , d is 12 bits long. O Maximum program memory size is 16 K words.
- Given that the main memory size is 32KB, the page size is 64B, the word size is 1B, and n-level paging is applied. What is the value of n?The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.A system uses pure segmentation (no paging). A segment table (see below) contains the following segment sizes and starting physical addresses. Segment Table Address Size 5 2048 2000 6 1024 400 2048 6000 1024 8000 11 Translate each of the following logical addresses (LA) into physical addresses (PA) or enter "illegal" if the LA is not within the segment. (1) LA = (5, 2000) (2) LA = (6, 2000) (3) LA = (7, 1000) (4) LA = (11, 500) Put your answer in the following blanks, one per blank, from left to right, case insensitive.
- Consider an 8-pin general purpose input/output port memory mapped to address adr_gpio_a . What does the following code do? ldr re, adr_gpio_a ldr r1, =0xfb str r1, [r®, #4] ldr r2, [r®] A. Sets pin 2 as input, the remaining pins (0,1, 3..7) as output, then reads from pin 2. B. Sets pin 2 as output, the remaining pins (0,1, 3..7) as input, then reads from every pin except pin 2. C. Writes the value Oxfb to the memory cell adjacent to the i/o port, then reads input from all of the pins in the port. D. Reads the input from the i/o port and applies a bit mask of Oxfb.Suppose that DS=1000H, SS= 2000H, CS=3000H, ES=4000H, BP=FFH, BX=FFFFH and DI=5H.i. Which memory locations are addressed by: MOV DL, [BP]?ii. Which memory locations are addressed by: MOV EAX, [BX+DI]?A processor uses a serial link to communicate with a keyboard for word processing. A typist using this keyboard can type at rates peaking at 120 words per minute, where a word is 6 characters (including spaces and punctuation). The characters will be transmitted from the keyboard in 8-bit ASCII with one stop bit and no parity. Only consider these and no special characters. The programmer writes setup and polling service routines based on a minimum baud rate, but then finds that the keyboard will only interface at 19.2 Kbaud. Will the polling service routine have to change? Why or why not? Baud Rates 300 600 1200 2400 4800 9600 19200