Simplify the diagram to one single transfer function. The solution is: T(s)= Please show all steps. 50(s-2)/(s^3+s^2+150s-100)
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- Find the following signals FT (Hint use FT pairs and FT propertise), Please write procedures (a) P3(t +2)+2P2(t- 1) (b) te-3u (1) +cos3t (c)3P (2t) For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). A v In *G白Q BIUS Paragraph Arial 10pt 田田田 EX: x X, T T 网 !!!if A=1100 and B=100 and C=101 write (F in Hex where F in Decimal is (A+B-C --Make a multiplication to the following numbers in the same base. Enter the plain result without parenthesis and base. (Example (111)s x (222)8 = (24642)8 , you need to enter 24642.) (13F)16 and (C7)16
- Consider the base 5 number 112s. Enter the base 5 digits in decimal form. place values 5- 25 5'-5 5° = 1 digits Now convert 112; to decimal representation. We get -5+ 13D 112, = -25+ Note: You can earn partial credit on this problem.Show graphical convolution for the following pair of signals please answer very soon will give rating surely All questions complete Answers neededWhat is the result of 01010 + 10101 in 2's complement notation? O-1 -31 31
- Are these functions orthogonal? rect((t+2)/4), rect((t– 2)/4) O Yes O No A Moving to another question will save this response. 71°F A C O Type here to search hp ort sc delete back 共 2$ 80 3 R K G 17 LLI-+A -B B C -A B ++C or or +A B -C -A ++C -A --B +C +A -B +C A B C D E what is/are the character that is/are considered informative? (choose the letter, if two or more answers, separate answer with comma and space. example: A, B, C, Db) Given the changed lines of code below, answer the following questions. ANALOG_COMPARE_SETUP: LDI R16,0 STS ADCSRA, R16 T LDI R16,0b00000000 STS ADCSRB, R16 LDI R16,0 STS ADMUX, R16 LDI R16,0b00001000 OUT ACSR, R16 RET What signals are now being compared? Determine if a comparator interrupt will occur (show work): Time (s) AINO (volts) AIN1 (volts) 1 4 5 4 1 4 1 0 1 4 5 4 5 0 0123456 Interrupt (y/n) n/a initial state
- Prove this using boolean algebra and show detailed solutionBC + AC + AB Answer must be AB + C (A XOR B)Number of essential prime implicants be X, prime implicants be Y, and implicants be Z for the minimised function (AB.C)=£-QL2567) then the product of XYZ is(i) Convert (101011000.1101)2 to Hexadecimal (ii) Using 1’s complement, perform subtraction X-Y and Y-X Where X= 1010100 Y=1000011