Titrations SHOW YOUR SOLUTIONS.1. The concentration of the Ba(OH)2 is 2.50 M. To neutralize 50.0 mL of a 16.0 M solution ofsulfuric acid, 640 mL of the base is needed.Ba(OH)2+ H₂SO4 ---> BaSO4 + 2H₂OA. TrueB. False2. A 132 mL sample of Ca(OH)2 solution was titrated with 2.45 M H₂SO4. 287 mL of the acidwas required to reach the endpoint of the titration. Based on these values, the Molarconcentration of the analyte is 5.33.H₂SO4 + Ca(OH)2 ---> CaSO4 + 2H₂OA. TrueB. False3. 10.60 mL of 0.3490 M aqueous HCI is required to titrate 66.00 mL of an aqueous solution ofNaOH to the equivalence point. The molarity of the analyte (NaOH) is .554 MNaOH + HCI ---> NaCl + H₂OA. TrueB. False

Answered: Image /qna-images/answer/21659bdd-7d30-4599-9452-d23fe2a399eb.jpg

SHOW YOUR SOLUTIONS. 1. The concentration of the Ba(OH)2 is 2.50 M. To neutralize 50.0 mL of a 16.0 M solution of sulfuric acid, 640 mL of the base is needed. Ba(OH)2+ H₂SO4 ---> BaSO4 + 2H₂O A. True B. False

SHOW YOUR SOLUTIONS. 1. The concentration of the Ba(OH)2 is 2.50 M. To neutralize 50.0 mL of a 16.0 M solution of sulfuric acid, 640 mL of the base is needed. Ba(OH)2+ H₂SO4 ---> BaSO4 + 2H₂O A. True B. False

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter6: Types Of Chemical Reactions And Solution Stoichiometry

Section: Chapter Questions

Problem 137CP

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Question

Titrations

SHOW YOUR SOLUTIONS.
1. The concentration of the Ba(OH)2 is 2.50 M. To neutralize 50.0 mL of a 16.0 M solution of
sulfuric acid, 640 mL of the base is needed.
Ba(OH)2+ H₂SO4 ---> BaSO4 + 2H₂O
A. True
B. False
2. A 132 mL sample of Ca(OH)2 solution was titrated with 2.45 M H₂SO4. 287 mL of the acid
was required to reach the endpoint of the titration. Based on these values, the Molar
concentration of the analyte is 5.33.
H₂SO4 + Ca(OH)2 ---> CaSO4 + 2H₂O
A. True
B. False
3. 10.60 mL of 0.3490 M aqueous HCI is required to titrate 66.00 mL of an aqueous solution of
NaOH to the equivalence point. The molarity of the analyte (NaOH) is .554 M
NaOH + HCI ---> NaCl + H₂O
A. True
B. False

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