Show that the Newton divided-difference polynomials 3 — 2(х + 1) + 0(х + 1)х + (x + 1)x(х — 1) and -1+ 4(x + 2) - 3(x + 2)(x + 1) + (x + 2)(x + 1)x - both interpolate the data (-2, –1), (-1,3), (0,1), (1, -1), (2,3). Why do the polynomials not violate the uniqueness property of interpolating polynomials?

Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter4: Complex Numbers
Section4.2: Complex Solutions Of Equations
Problem 6ECP: Find a fourth-degree polynomial function f with real coefficients that has 2, 2, and 7i as zeros.
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Show that the Newton divided-difference polynomials
3 — 2(х + 1) + 0(х + 1)х + (x + 1)x(х — 1) and
-1+ 4(x + 2) - 3(x + 2)(x + 1) + (x + 2)(x + 1)x
both interpolate the data (-2, –1), (-1,3), (0,1), (1, -1), (2,3).
Why do the polynomials not violate the uniqueness property of interpolating polynomials?
Transcribed Image Text:Show that the Newton divided-difference polynomials 3 — 2(х + 1) + 0(х + 1)х + (x + 1)x(х — 1) and -1+ 4(x + 2) - 3(x + 2)(x + 1) + (x + 2)(x + 1)x both interpolate the data (-2, –1), (-1,3), (0,1), (1, -1), (2,3). Why do the polynomials not violate the uniqueness property of interpolating polynomials?
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