S = 4. Let (xn) be a bounded sequence and let s sup{xn ne N}. Show that if s &{xn: nЄ N} then there is a subsequence of (xn) that converges to s

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.2: Arithmetic Sequences
Problem 48E
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please help proof this and be specific so i can undersatnd. also please include the theorem that you are using to solve this too please

S =
4. Let (xn) be a bounded sequence and let s
sup{xn ne N}. Show that if s &{xn: nЄ N}
then there is a subsequence of (xn) that converges to s
Transcribed Image Text:S = 4. Let (xn) be a bounded sequence and let s sup{xn ne N}. Show that if s &{xn: nЄ N} then there is a subsequence of (xn) that converges to s
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