Question 9 of 34 How many moles of aluminum are required to completely react with 107 mL of 6.00 M H₂SO4 according to the balanced chemical reaction: 2 Al(s) + 3 H₂SO4(aq) →Al₂(SO4)3(aq) + 3 H₂(g) Submit

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.87PAE
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Question
STARTING AMOUNT
O
esc
X
2
W
#m
3
How many moles of aluminum are required to completely react with 107 mL of
6.00 M H₂SO4 according to the balanced chemical reaction:
0.428
ADD FACTOR
e
* ( )
mL H₂SO4
0.0374
4
2 Al(s) + 3 H₂SO4(aq) → Al₂(SO4)3(aq) + 3 H₂(g)
98.08
M H₂SO4
%
5
Question 9 of 34
1
2
3
g H₂SO4
6
107
6.022 x 1023
gAl
MOO
D
y
&
ANSWER
7
h
428
1000
mol H₂SO4 g Al₂(SO4)3
8
6.00
RESET
0.001
5
0.963
LH₂SO4
CD
Mar 2
5:28
Submit
+
Transcribed Image Text:STARTING AMOUNT O esc X 2 W #m 3 How many moles of aluminum are required to completely react with 107 mL of 6.00 M H₂SO4 according to the balanced chemical reaction: 0.428 ADD FACTOR e * ( ) mL H₂SO4 0.0374 4 2 Al(s) + 3 H₂SO4(aq) → Al₂(SO4)3(aq) + 3 H₂(g) 98.08 M H₂SO4 % 5 Question 9 of 34 1 2 3 g H₂SO4 6 107 6.022 x 1023 gAl MOO D y & ANSWER 7 h 428 1000 mol H₂SO4 g Al₂(SO4)3 8 6.00 RESET 0.001 5 0.963 LH₂SO4 CD Mar 2 5:28 Submit +
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