Question #11 What is the ratio of the root-mean-square velocities (Urms): (ratio = urms O2: Ums Xe) ? of oxygen (O2) molecules to that of xenon atoms (Xe) • at 323 K O ratio of effusion of O2: Xe = 4.103 O ratio of effusion of O2: Xe = 1.002 O ratio of effusion of 02: Xe = 2.026 O ratio of effusion of 02 :Xe = 20.03
Question #11 What is the ratio of the root-mean-square velocities (Urms): (ratio = urms O2: Ums Xe) ? of oxygen (O2) molecules to that of xenon atoms (Xe) • at 323 K O ratio of effusion of O2: Xe = 4.103 O ratio of effusion of O2: Xe = 1.002 O ratio of effusion of 02: Xe = 2.026 O ratio of effusion of 02 :Xe = 20.03
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter5: Gases, Liquids, And Solids
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Transcribed Image Text:Gram's Law of Effusion: rate of effusion
MM
rate effusion A
MMB
rate effusion B
{
I MMA
3RT
Hrms =
{
MM
Urms = root mean square velocity ( Hrms ) of a gas molecule in meters/sec
• R = 8.31 (kg - m2 )/(s² - mol-K) Ideal Gas Constant in SI units
• MM = molar mass - kg/mol in SI units ~ 02 = 0.03200 kg/mol
Question #11
What is the ratio of the root-mean-square velocities (ums):
(ratio = urms 02: Urms Xe) ?
• of oxygen (02) molecules to that of xenon atoms (Xe)
• at 323 K
O ratio of effusion of O2: Xe
e = 4.103
O ratio of effusion of O2: Xe = 1.002
O ratio of effusion of 02 :Xe = 2.026
O ratio of effusion of 02 :Xe = 20.03
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