QL Match list (1) with list (IT) and select the correct answer?Ja]Type of chip1 Continuous chip.2 Serrated chips.List IList IIType of material being machined and the cutting conditions.A cast irons are machined at low cutting speedsB ductile materials at low-to-medium cutting speedsCtitanium alloys machined at higher cutting speedsductile work materials are cut at high speeds and relatively smallfeeds and depths3 Discontinuous chip.Continuous chip with4built-up edges.DTypes of WeldsGeometryNo.Flange weldA.2fillet weld3 Surfacing weld4Plug weldDSlot weld6groove weldlelProcessGrain flow of the part1 Forging2 Machiningв3 Casting

Different types of metal forming processes used in engineering applications are: Forging Casting…

QL Match list (1) with list (T) and select the correct answer? la Type of chip 1 Continuous chip. 2 Serrated chips. 3 Discontinuous chip. Continuous chip with List I List II Type of material being machined and the cutting conditions. A cast irons are machined at low cutting speeds B ductile materials at low-to-medium cutting speeds C titanium alloys machined at higher cutting speeds D ductile work materials are cut at high speeds and relatively small feeds and depths 4 built-up edges. [b| No. Types of Welds Geometry Flange weld fillet weld 3 Surfacing weld Plug weld 5 Slot weld groove weld F lel Process Grain flow of the part 1 Forging 2 Machining B 3 Casting C

QL Match list (1) with list (T) and select the correct answer? la Type of chip 1 Continuous chip. 2 Serrated chips. 3 Discontinuous chip. Continuous chip with List I List II Type of material being machined and the cutting conditions. A cast irons are machined at low cutting speeds B ductile materials at low-to-medium cutting speeds C titanium alloys machined at higher cutting speeds D ductile work materials are cut at high speeds and relatively small feeds and depths 4 built-up edges. [b| No. Types of Welds Geometry Flange weld fillet weld 3 Surfacing weld Plug weld 5 Slot weld groove weld F lel Process Grain flow of the part 1 Forging 2 Machining B 3 Casting C

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Expert Q&A Done The top surface of a rectangular workpart is machined using a peripheral milling operation. The workpart is 735 mm long by 50 mm wide by 95 mm thick. The milling cutter, which is 60 mm in diameter and has five teeth, overhangs the width of the part equally on both sides. Cutting speed = 80 m/min, chip load = 0.30 mm/tooth, and depth of cut = 7.5 mm. (a) Determine the time required to make one pass across the surface, given that the setup and machine settings provide an approach distance of 5 mm before actual cutting begins and an overtravel distance of 25 mm after 1.2 9. 20 65 73 actual cutting has finished v in seconds. (b) What is the maximum material 3.9 239 removal rate during the cut v in mm3/sec? 0.127 5
We have a rectangular piece. We wish to manufacture a parallel slot along thepiece in a vertical milling machine and 50 cm from the edge. The width of the slot is 40 mm. TheDepth of the slot is 25 mm. For this, several rough cutting steps and aFine cut with a depth of 0.20 mm. The depth for each of the steps ofrough cut is limited to 1.75 mmAditional information:What is the number of blades used for the rough cutting steps?What is the number of blades used for the fine cutting step?
Q1:- Put a mark of True or false for below:- (a):- The milling cutting tool has a single cutting edge? (b):- At the break-even point, the total revenue equals the total cost? (c):- The right-hand rule is used to define machine axes? (d):- Design error is a simple mistake? (e):- The quality of products is poor in mass production? (f):- Allowances must be left before turning? (g):- Up-ward milling is better than down-ward milling?
In an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle  = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work done
Problem 2. Turning Consider Step 2 (Turn Shoulder) in machining the flashlight handle (Figure 2). STEP 1: CUT TO LENGTH STEP 2: TURN SHOULDER 0.600 1.0" 3.000 -0.440 Figure 2. Turning step for Problem 2. i) Calculate the (1) cutting time (in s), (2) the material removal rate (in in3 /s or mm3/s) for this cut, assuming you remove all of the material with one pass (i.e., depth of cut d = (1"-0.6")/2 = 0.2"), and (3) the power (hp or W) required for this turning operation: Consider the following scenarios: Feed (f) in/rev Rotational Speed Cutting Time MRR Power (n) in RPM 0.02 1000 ? ? ? 0.025 900 ? ? ? 0.03 800 ? ? ? 1 j) What changes could you make to the process if you needed to decrease the power requirement?
=te average Vc = TDN 1000 TS sin e Where is Chip Reduction Coefficient ve is cutting speed te is thickness of cut chip T is thickness of non-cut chip S is feed rate is cutting angle = 45⁰ D is diameter of workpiece = 40mm Results Depth of cut (a) mm 2 NNNN 2 2 m/min 2 Cutting speed (Vc) m/min 500 500 500 500 500 Feed rate (S) mm/rev 0.11 0.14 0.20 0.24 0.28 tc; tc₂ tc3 0.39 0.58 0.43 0.42 0.62 0.5 0.34 0.42 0.32 0.9 0.96 0.95. 0.92 0.85 0.85 te average (mm) H (mm) Chip Reduction Coefficient (2) Discussion 1- Why the thickness of chip after cutting process is larger than chip thickness before cutting process? 2- What is the reason of variety of the chips types with cutting conditions? 3- What is the difference in the feed rate between turning machining and milling machining? 4- Draw chart between feed rate (S) and chip reduction coefficient (A) with discuss it.
Q4 Tool life of a turning tool is given by VT0.12xfP.7xd3=C at a cutting speed (V) of 25m/min, feed(f) 0.25 mm/rev and job diameter(d) 4 mm, the tool life was 53 minutes. Calculate (i) Tool life if cutting speed increased by 20 % [3]
Puanlar) 16 The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C=450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. V vT" = C. %3D Ce Tm 1. %3D 19 fv 25 31 37 43 49 187.9 m/min b) 325.8 m /min 275.8 m/min d) 226.6 m/min
Question 3. a. A cast iron component for motorcycle is to be turned with machine settings of feed = 0.22 mm/rev, and speed = 100 m/min. The cutting tool is a carbide tip with a nose radius of 1.2 mm and the rai for the material at a cutting speed of 100 m/min is 1.3. Calculate the surface roughness for this cut. [6 marks]
1. Most common instrument used in the mechanical gages is the dial indicator, which of the following applications cannot be measured by the dial indicator? (a) All of them (b) Perpendicularity (c) Runout (d) Circularity (e) Roughness 2. The main mechanism for the flank wear on the single point cutting tool is: (a) Oxidation wear (b) Adhesion wear (c) None of them (d) Diffusion wear (e) Plastic deformation 3. Higher cutting speeds and temperatures are the main mechanism of the following tool wear mechanism: (a) Diffusion wear (b) Abrasion wear (c) None of them (d) Adhesion wear (e) Plastic Deformation
The following data was obtained from an orthogonal cutting test. Rake angle = 20° Depth of cut = 6 mm Feed rate = 0.25 mm/rev Cutting speed = 0.6 m/s Chip length before cutting = 29.4 mm Vertical cutting force = 1050 N Horizontal cutting force = 630 N Chip length after cutting = 12.9 mm Using Merchant's analysis, calculate (a) Magnitude of resultant force, (b) shear plane angle, (c) friction force and friction angle, and (d) various energies consumed.
wing (3) You are to produce a machine part (a shaft) with different diameters S0mm.35mm and 30mm with thread and keyway at the end of the shaft (a) How many machines and cutting tools will you use to produce this part 1