Q1//: For the loaded area below determine the increase in vertical stress at depth of 4m below point A A qs= 175 KN/m2 A qs= 100 KN/m2 2.0m A qs= 100 KN/m2 3.0m A 6.0 m 4.0 m
Q: The soil is having a saturated unit weight 18.0 kN/m and dry unit weight of 11 kN/m. The water table…
A: Saturated unit weight of soil = 18KN/m3 Dry unit weight of soil = 11KN/m3 Given two diagrams in Fig…
Q: P2: A flexible L-shaped raft shown in Figure applies a uniform pressure of 60 kN/m? to the…
A: Stress Increase at Any Depth z Using Boussinesq Equation :σ=3Q2πz2[1(1+rz2)52]Where Q = Applied…
Q: A river 5 m deep consists of a sand bed with a saturated unit weight of 20 kN/m3, yw = 9.81 kN/m3.…
A: Given- Depth of sand bed = 5m Saturated unit weight γsat=20 KN/m3 Unit weight of water γw=9.81 KN/m3…
Q: 1. Determine the increase in vertical stress at a depth of 7 m below the point B. Point loads of…
A: using boussenique's equationσ=QZ232π11+rz25/2z=7 mr1=3 mr2=5 m
Q: Q.3) Determine the increase in vertical stress at a depth 4 m below point A due to surface loads…
A: The Stress at a Depth z below Surface ,Due to a Point Load is Given by Boussinesq's Formula , Stated…
Q: Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure P6.2).…
A: Applying Boussinesq's Equation: ∆σz=3P2πz21+rz25/2 ...(1)
Q: A flexible circular area of radius 3.3 m. is uniformly loaded by q = 315 kN/m². Determine the…
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Q: 2. The ground water level in a thick, very fine sand deposit is located 2.0 m below the ground…
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Q: Tpis) Refer to Figure 3.67, a flexible rectangular area is subjected to a uniformly distributed load…
A: Given Case 1 : r = 0 & z = 3 m and Case 2 : r = 2.2 m & z = 3 m Q = load = 225×6×3 =…
Q: Point loads of magnitude 9, 18, and 27 kN act at A, B, and C, respectively (Figure 8.23). Determine…
A: Boussinesq’s formula for calculating stress below point load:
Q: 10.17 Refer to Figure 10.47 A flexible rectangular arca is subjected to a uniformly distributed load…
A: Introduction- Vertical stress is among the most significant pressures encountered by constrained…
Q: Q.3) Detemine the increase in vertical stress at a depth 4 m below point A due to surface loads…
A: Given:- The stresses is given with different magnitude qs = 100 kN/m2 , qs = 160 kN/m2 , qs = 225…
Q: 2. The ground water level in a thick, very fine sand deposit is located 2.0 m below the ground…
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Q: capillary rise is of 50% saturated. Saturated unit weight of soil is 21.6 kN/m³. Void ratio = 0.40.…
A: Given Soil is 50% saturated in capillary rise zone
Q: Point loads of magnitude 100, 200, and 400 kN act at A, B, and C, respectively. the increase in…
A: The point load at A, B and C are 100KN, 200KN and 400KN respectively.
Q: C 6 m B A 5 m 3 m 6 m 3 m Fiq 23 - Prob 23
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Q: Point loads of magnitude 100, 200, and 400 kN act at A, B, and C, respectively. the increase in…
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Q: Problem (4.4): Given: q= 100 kN/m. Find: The vertical stress o, at points 0, 1, and 2 shown in Fig.…
A: Uniformly Loaded Line of Finite Length Case: Consider the free body diagram of given loading on soil…
Q: Referring in the Fig. 2 below, B = 6m and q =150 kPa. For Point P, z = 2m and x = 1.5m. Determine…
A: Given Data: The width of the strip footing is B=6 m. The loading of the strip footing is q=150 kPa.…
Q: Q2/ For the uniformly distributed loaded area as shown below, estimate the vertical stress at point…
A: A uniformly distributed load (UDL) is a load that is distributed across the region of an element…
Q: A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs =…
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Q: 10.19 Refer to Figure 10.46. A flexible rectangular area is subjected to a uniformly dis- tributed…
A: Given data: q = 225 kN/m2 Total load on rectangular area = Q= q×Area=225 kN/m2×6 m×3 m=4050 kN r =…
Q: Calculate the vertical stress at a depth of 50 ft below a point 10 ft oubide the corner (along the…
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Q: Using equation 10.35, determine the vertical stress (Aoz) increase below the center of the loaded…
A: The given data is shown below: z=2,4,6,8 and 10m
Q: SITUATION: Refer to Figure below. Point loads of magnitude 500 KN, 750 KN, 800 KN, and 1000 KN act…
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Q: 4. A 10 m thick layer of shift, saturated clay is underlain by a layer of sand. The sand is under…
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Q: A 5 m-thick clay (Gs = 2.65, water content = 0.28) is overlain by a 4.50m-thick layer of sand (Gs =…
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Q: Н.О 4 Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure below).…
A: The given data is: Load at point B (QB) = 100 kN Load at point C (QC) = 200 kN Load at point D (QD)…
Q: Three point loads 10, 7.5 and 9 MN, act in line 5 m apart near the surface of a soil mass, as shown…
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Q: A river 5m deep consists of a sand bed with saturated unit weight of 20 kN/m³, Yw = 9.81 kN/m³. The…
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Q: The Two columns A and B situated 6 m apart. Column A transfers a load of 500 kN, and column B…
A: Given data: Column A load= 500 kN Column B load= 250 kN Distance between the columns=6 m. Z=2m
Q: Saturated clay has the void ratio of 1.65 and density of solids (or density of solid particles) of…
A: Answer We know that horizontal total stress for at rest earth pressure is given by σH = Ko*σV σH =…
Q: Point loads of magnitude 9, 18, and 27 kN act at A, B, and C, respectively (Figure 6.27). Determine…
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Q: EX: The uniformly distributed vertical load on the rectangular area is q1 =100 kN/m², and the…
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Q: H.Q 4 Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure below).…
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Q: 1200 kN 1500KN Q.3. Determine the vertical stress at points a and b due to the shown external loads.…
A: we will use boussinesq equation.
Q: Q.3) Determine the increase in vertical stress at a depth 4 m below point A due to surface loads…
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Q: An aquifer is overlain by 15 m of jointed rock. The density of the rock is 2500 kg/m. The density…
A: Note: Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question…
Q: Figure below shows an embankment load on a silty clay soil layer. Determine the stress increase at…
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Q: Determine the vertical stress increase, Aoz, at point A with the following values: q1 = 90 KN/m; q2…
A: Given: Line loads Vertical distance Radial distance To find: Vertical stress increase at point A to…
Q: Determine the vertical stress increase 6 m below point E.
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Q: 5- A flexible rectangular area is subjected to a uniformly distributed load of q=250 Ib/ft.…
A: Given Data:L=6B=3q=250lb/ft2=4500lbz=6ft
Q: H.Q 4 Point loads of magnitude 100, 200, and 400 kN act at B, C, and D, respectively (Figure below).…
A: Given that: Point load at B, QB=100 kN Point load at C, QC=200 kN…
Q: The plan of a flexible rectangular loaded area is shown in Figure 6.30. The uniformly distributed…
A: Solution: The equation for determining the increase in stress on a flexible rectangular area at a…
Q: Problem 1: Point loads of magnitude 100, 200, and 400 kN act at A, B, and C, respectively. Determine…
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Q: The circular flexible area uniformly loaded (q=320KN/m^2). Determine the change in vertical stress:…
A: Given: The uniformly loaded area (q) is 320 kN/m2. Consider the figure,
Q: H.W: A layer of sand 5 meters deep overlies a thick bed of clay. calculate the vertical, horizontal,…
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Q: A flexible square area (2.4 m. x 2.4 m.) is subjected to a uniformly distributed load of q = 178…
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- CLO 1: Determine the maximum shear stress in MPa if P = 115 kN. 20 mm 25 mm 20 mm 3somm 28.395 O 72.282 32.467 21.550 45mmSHEAR STRESS 2 If the T-beam is subjected to a vertical shear of V = 60 kN, determine the maximum shear stress in the beam. Also, compute the shear-stress jump at the flange-web junction AB. Sketch the variation of the shear-stress intensity over the entire cross section. VQ TRỊ = It 100 mm (60 kN)Q 100 mm 75 mm 100 mm I(300) B' VQ TB = VQ 150 mm It I(100) A V = 60 kNRefer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine the increase in vertical stress at point A located z = 15 ft below the surface. Given: x = 27 ft. Figure P6.4
- Given The uniformly loaded area shown below is built on the ground surface and carries a load of 160 kPa. D1-8 m D2 = 12 m D3 = 4 m D4-5 m D5 = 3 m D1 D3 D2 D5 A D4 Required Determine the vertical stress increment at a depth of 10 m below Point A. Provide answer in kN/m², to the nearest 100th.Based on the geometry calculation of the drawn Mohr circle, what is the minor principal stress (o3) [unit: kN/m2]. oy= 120 kN/m2, T = 40 kN/m?, ơy = 300 kN/m2, and e = 20°. %3D B A T. TyB A 6.0m Ce 5.0 m 4
- From distace x = 0 to x = 5m, the slope of the shear diagram is equal to 10 KN/m. The change in shear between these two points is equal to * 50KN O 10KN 5KN none of the above3. The vertical stress o̟ under the corner of a rectangular area subjected to a uniform load of intensity q is given by the solution of Boussinesq's equation: 2mn /m² +n² +1 m² + n² +2 + sin 47 m² +n² +1+m²n² m² +n² +1 2mn/m² +n² +1 m² +n² +1+m²n² O = because this equation is inconvenient to solve manually, it has been reformulated as 0̟ = qf (m,n) where f.(m,n) is called the influence value and m and n are dimensionless ratios, with m=a/z and n=b/z and a and b are defined in the following figure. 1 The influence value is then tabulated, a portion of which is given in the following table n = 1.2 n = 1.4 0.03007 0.05894 0.08561 n = 1.6 0.1 0.02926 0.03058 0.2 0.05733 0.05994 0.3 0.08323 0.08709 0.4 0.10631 0.10941 0.11135 0.13003 0.14749 0.16199 0.5 0.12626 0.13241 0.15027 0.16515 0.17739 0.6 0.14309 0.7 0.15703 0.8 0.16843 0.17389 If a=4.6 and b=14,compute o̟ at a depth 10 m below the corner of a rectangular footing that is subject to a total load of 100 t (metric tons). Note that q is…Determine the flexural stresses using transformed-area method. 2 #25 70 mm 560 mm M = 300 kN• m n = 9 700 mm 4 #32 70 mm 400 mm
- The T section is shown in Figure below is the cross-section of a beam. The beam is subjected to a uniform distributed load = 4 kN/m. The N.A is located at 34.7 mm from the bottom and that IxA =10.64x106 mm. Determine (a) the maximum shearing suess (b) the shearing stress at 15 mm from the bottom face. Q2 %3D 20mm 4 kN/m 120mm A 34.7 mm 20mm lm 3m 1m 220mm TTA 50-kip vertical downward column load acts at the centroid of a 4-ft-square (4 ft by 4 ft) normal-weight concrete footing. The footing concrete has a unit weight of 150 pcf. The bottom of this footing is 3 ft below the level ground surface and the top of the footing is flush with the ground surface. The groundwater table is at a depth of 15 ft below the ground surface. Compute the bearing pressure at the base of the footing. Answer: Opsf Oksf A vertical force of 57.2 kips acts on a 4.0 ft x 4.0 ft area. Compute the induced vertical stress, Aoz, at a point 4.0 ft (zf = 4 ft) below the center (xf = 0 ft) of this square area using the following Boussinesq chart. Width = B Square Loaded Area 1.0 05 0.5 1.0Two columns A and B are situated 6 m apart. Colum A transfers a load of 500 kN and column B, a load of 250 kN. Determine the resultant vertical stress on a horizontal plane 20 m below the ground surface below point A. a.12.4 kPa b.232.49 kPa c.29.9 kPa d.59.8 kPa