Prove that, for all integers n ≥ 0 and 0 ≤ k ≤n, we have (x+¹)=()+(*+¹) ++ (1) n+ k+1 k Hint: the left hand side is the number of k + 1-element subsets of {1,..., n+1}. Show that the right hand side is also equal to this number by grouping these subsets according to their largest element.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
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Prove that, for all integers n ≥ 0 and 0 ≤ k ≤ n, we have
k+
(+) = (3) + (*+¹) ++ (1)
Hint: the left hand side is the number of k + 1-element subsets of {1,...,n+1}. Show that the
right hand side is also equal to this number by grouping these subsets according to their largest
element.
Transcribed Image Text:Prove that, for all integers n ≥ 0 and 0 ≤ k ≤ n, we have k+ (+) = (3) + (*+¹) ++ (1) Hint: the left hand side is the number of k + 1-element subsets of {1,...,n+1}. Show that the right hand side is also equal to this number by grouping these subsets according to their largest element.
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