Proof: Let n be any integer such that n ≥ 2. [We will show that for every integer n ≥ 2, P(n + 1, 3) = n³ – n.]. Since n ≥ 2, then n + 1 ≥ 3. Start by applying the first version of Theorem 9.2.3. (Simplify your answers completely.) P(n + 1, 3) = ] (n)n - - 1)(n-2)! ] (n)xn- - 1) = n³ - n Hence, for every integer n ≥ 2, P(n + 1, 3) = n³ – n.
Proof: Let n be any integer such that n ≥ 2. [We will show that for every integer n ≥ 2, P(n + 1, 3) = n³ – n.]. Since n ≥ 2, then n + 1 ≥ 3. Start by applying the first version of Theorem 9.2.3. (Simplify your answers completely.) P(n + 1, 3) = ] (n)n - - 1)(n-2)! ] (n)xn- - 1) = n³ - n Hence, for every integer n ≥ 2, P(n + 1, 3) = n³ – n.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.2: Properties Of Division
Problem 51E
Related questions
Question
![Proof: Let n be any integer such that n ≥ 2. [We will show that for every integer n ≥ 2, P(n + 1, 3) = n³ – n.]. Since n ≥ 2, then n + 1 ≥ 3. Start by applying
the first version of Theorem 9.2.3. (Simplify your answers completely.)
P(n + 1, 3) =
3
= n - n
n³.
Denxen.
1)(n- 2)!
)₁
] (n)(n - 1
- 1)
Hence, for every integer n ≥ 2, P(n + 1, 3) = n³
· n.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a2c9ae4-718a-4288-bbc7-9ce9838a8ae1%2F3be634aa-d471-4b2a-bab1-b44563e40d45%2F2vuh8d_processed.png&w=3840&q=75)
Transcribed Image Text:Proof: Let n be any integer such that n ≥ 2. [We will show that for every integer n ≥ 2, P(n + 1, 3) = n³ – n.]. Since n ≥ 2, then n + 1 ≥ 3. Start by applying
the first version of Theorem 9.2.3. (Simplify your answers completely.)
P(n + 1, 3) =
3
= n - n
n³.
Denxen.
1)(n- 2)!
)₁
] (n)(n - 1
- 1)
Hence, for every integer n ≥ 2, P(n + 1, 3) = n³
· n.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 3 images
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage