Problem 2 The switch in the circuit below is opened at t=0, find V(t) for t>=0 and calculate the initial energy stored in the capacitor.
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- An AC circuit contains a 24 resistor, a 15.9-mH inductor, and a 13.3F capacitor connected in parallel. The circuit is connected to a 240-V, 400-Hz power supply. Find the following values. XL=XC=IR=AIL=AIC=AP=WVARsL=VARsC=IT=AVA=PF=%=Consider the circuit shown below, with an initially uncharged capacitor C and two identical resistors R. R O www V I C I₂ R C R At the instant the switch is closed, the current through the capacitor will be: zero At the instant the switch is closed, the current through the right-side resistor will be: V/R, directed Up After the switch has been closed for a very long time, it is opened. The current through the right-side resistor will be V/R, directed Down The switch is closed at t = 0. At t = ~ (long after) the current through the right-side resistor will be: V/2R, directed Down ✓ The switch is closed at t = 0. At t = ~ (long after) the current through the capacitor will be: V/2R, directed Up After the switch has been closed for a very long time, it is ope ed. The current through the be? V/R, directed Down pacitor willIn the circuit shown in Figure, the switch S is closed at time t = 0. the voltage across the inductance at t = 0+ 3.02 10V A) 2V B 4V c) -6V D) 8V S 4F 492 HIMM WWW 49 ell
- In the circuit below, Find the voltage across the inductor at time t = 0.000909 s. The values are V1 = 146V, R = 4.4 ohms, L =0.02 henriesThe figure below shows a simple RC circuit with a 3.30-μF capacitor, a 4.40-M resistor, a 9.00-V emf, and a switch. What are the following exactly 9.00 s after the switch is closed? (a) the charge on the capacitor 13.7204 UC (b) the current in the resistor 0.0110522 x Your response is off by a multiple of ten. HA (c) the rate at which the capacitor is storing energy μW (d) the rate at which the battery is delivering energy μWFor R1=9000, R2=2000, R3=6000, R4=5000, C1=0.006, C2=D0.002 & 11=0.007 A in the shown circuit, obtain the energy stored in each capacitor under dc conditions. C2 R4 ŽR3 ER2 ŽRI C1= Energy stored in C1= Energy stored in C2=
- The circuit in Figure has been connected for a long time. If the battery is disconnected, how does it take the capacitor to discharge to 1/20 of its initial voltage? Take R₁ = 2.00 Q, R₂=4.00 Q, R3-7.00 Q, R4 = 2.00 Q and C= 5.00 uF and ε = 14.0 V. (Your result must be in us. Include 2 digit after the decimal point and maximum of 2% of error is accepted in your answer.) E R₂ R₂ BAFor the circuit shown in Figure Q2, determine the followi (a) The current in the inductors L1 and L2. (b) The voltage across the capacitors Cl and C2. (c) The total energy stored in the circuit. (d) The total power supplied by the source. 30V II RI -000-m 20mH 1052 50mH 2 R2 2002 300µF -000 30ml 91 300µF CI 600 μF R3 30Ω C3The capacitor in the circuit is initially uncharged and the switch S is suddenly closed at t=0. Find the current on resistor R: at to Take R₁-4R and R 3R. A) = B) 6 25 D) E) SIA R₂ FF R₁
- 9) Switch S1 closes at t=0. What is the final voltage across the capacitor? What is the current through the capacitor at t=0? How long does it take the capacitor to reach it’s final voltage?The figure below shows a simple RC circuit with a 3.50-µF capacitor, a 3.60-MQ resistor, a 9.00-V emf, and a switch. What are the following exactly 6.50 s after the switch is closed? S C R (a) the charge on the capacitor (b) the current in the resistor µA (c) the rate at which the capacitor is storing energy (d) the rate at which the battery is delivering energyThe switch in the following circuit closes at t-0. If the capacitor is initially discharged, calculate the voltage on the capacitor at t-3s. (R-50KQ, C-33uF) 50 k2 15 V 33 jul