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Find Electric Force on point 3
Find the Electric Field on point P
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- A sphere has a net charge of 8.05 nC, and a negatively charged rod has a charge of 6.03 nC. The sphere and rod undergo a process such that 5.00 109 electrons are transferred from the rod to the sphere. What are the charges of the sphere and the rod after this process?(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 10.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol. (b) Imagine adding electrons to the pin until the negative charge has the very large value 1.00 mC. How many electrons are added for every 109 electrons already present?There are very large numbers of charged particles in most objects. Why, then, don't most objects exhibit static electricity?
- (a) How strong is the attractive force between a glass rod with a 0.700 C charge and a silk cloth with a 0.600 C charge, which are 12.0 cm apart, using the approximation that they act like point charges? (b) Discuss how the answer to this problem might be affected if the charges are distributed over some area and do not act like point charges.Consider the following. 60.0⁰ 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C = -4.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The field would be unchanged. O The magnitude of the field would be doubled. O The magnitude of the field would be halved. O The magnitude of the field would be quadrupled.60.0 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.90 pC, B = 6.50 PC, and C= -4.80 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC= 1 x 10-12 C.) magnitude 210191.91 ✓N/C X 77.605 direction What are the components of the net electric field? Can you then use these to find the direction?" counterclockwise from the +x-axis
- Consider the following. 60.0⁰ B 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C= -4.30 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction o counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The field would be unchanged. O The magnitude of the field would be doubled. O The magnitude of the field would be quadrupled. O The magnitude of the field would be halved.Consider the following. 0.500 mm 60.0 (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 7.10 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-12 C.) magnitude N/C direction ° counterclockwise from the +x-axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? The magnitude of the field would be doubled. The magnitude of the field would be halved. Does the electric field at cell A include the electric field generated by cell A?The field would be unchanged. O The magnitude of the field would be quadrupled.The two spherical shell has a charge of 91 = 0.30nC and q2 = 0.5nq. The radius of r1=7.5cm and r2 = 2.5cm. What is the new votage value in volts, after the charge transfer is completed between the two spheres? 9:
- Problem 3: Three charges are located as shown in the figure, with values q = 4.9 x 10-16 C, 92 = -1.8 x 10-16 C, 93 = 6.75 x 10-16 C. The charges are separated by d7 = 2.3 × 10-6 m and dz = 1.4 x 10-6 m. 93 d, Otheexpertta.com Part (a) What is the force of g2 ong in the x direction, F,? Give your answer in newtons, and recall k= 8.988 x 10° N m2/C2. F= 1.5 * 10-10 F = 1.5E-10 Correct! Part (b) What is the force of q3 on q in the y direction, F,? Give your answer in newtons. Grade Summary Fy = 1.51 * 10-9 Deductions 2% Potential 98%Two identical point charges (q=+9.00 x 106 C) are fixed at opposite corners of a square whose sides have a length of 0.420 m. A test = charge (40 -9.20 x 108 C), with a mass of 4.80 x 108 kg, is released from rest at one of the corners of the square. Determine the speed of the test charge when it reaches the center of the square. Number i Units m/s 40Three point charges are located as shown in the figure. q1 =-9 x 10-12 [C) and d =5 [cm] 92 =1 x 10-12 (C] and d2 = 1 (cm] 93 =-4 x 10-2 (C) and d3 = 7 (cm] 93 d3 a. the th. 92 E =L [N/C] d, d, b. What is the direction of E1, the electric field created by the charge q at the origin. c. Calculate E, the magnitude of the electric field created by the charge g at the origin E [N/C) What is the direction of E 2, the electric field created by the charge q at the origin e.l Calculate Es, the magnitude of the electric field created by the charge q at the origin. E = (N/C] f.L What is the direction of E 1, the electric field created by the charge q at the origin. oi gK... Suppose that: E 3i+3 IN/C E-2i+1 N/C Ey-1i+1 IN/C Calculate the net electric field vector created at the origin (DO NOT USE THE VALUES FOUND IN THE PREVIOUS PARTS) E Î IN/C) h A charge qo equal to -1.6 x 10-19 is located at the origin. The net electric field at the origin and the total force applied on the charge g will have:…
