Problem 1: Assume the atmosphere can be treated as isothermal. In this case, the density varies exponentially with altitude as: P= Po (e) Po is the density at the base of the column of air (sea level). Assume the atmosphere as if it were pure nitrogen (N2) with mass 28 amu at a temperature of 288 K and that Po 1.23 kg/m3. Note that 1 amu = 1.66 x 10-27 kg. What is the mass per square meter of a column of this gas between y = 1500 m and y = 4500 m?

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Problem 1: Assume the atmosphere can be treated as isothermal. In this case, the density varies
exponentially with altitude as:
P = Po (e 7+²)
Po is the density at the base of the column of air (sea level). Assume the atmosphere as if it were pure
nitrogen (N2) with mass 28 amu at a temperature of 288 K and that Po 1.23 kg/m3. Note that 1 amu =
1.66 x 10-27 kg. What is the mass per square meter of a column of this gas between y = 1500 m and y =
4500 m?
Transcribed Image Text:Problem 1: Assume the atmosphere can be treated as isothermal. In this case, the density varies exponentially with altitude as: P = Po (e 7+²) Po is the density at the base of the column of air (sea level). Assume the atmosphere as if it were pure nitrogen (N2) with mass 28 amu at a temperature of 288 K and that Po 1.23 kg/m3. Note that 1 amu = 1.66 x 10-27 kg. What is the mass per square meter of a column of this gas between y = 1500 m and y = 4500 m?
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